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alukav5142 [94]
3 years ago
11

The table shows the concentration of a reactant in the reaction mixture over a period of time.

Chemistry
1 answer:
zvonat [6]3 years ago
6 0

Answer:

C. 2.0 x 10⁻³

Explanation:

The average rate of a reaction is the rate of change of the concentration of the reactants (or products) with time.

The average rate of the reaction = - (ΔC)/(Δt).

∵ The concentration of the reactants changes from 1.8 M to 0.6M for 580 s.

∴ The average rate of the reaction over the first 580 seconds

   = - (ΔC)/(Δt) = - [(0.6M) - (1.8 M)]/[(580.0 s) - (0.0 s)] = 2.0 x 10⁻³ M.s⁻¹.

So C. 2.0 x 10⁻³ is the right answer

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<span> </span>

Answer is: volume is 20 mL.<span>
c</span>₁(CH₃COOH) = 2,5 M.<span>
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V</span>₁(CH₃COOH) = ?<span>
c</span>₁(CH₃COOH) · V₁(CH₃COOH) = c₂(CH₃COOH) · V₂(CH₃COOH).<span>
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8 0
3 years ago
What is the significance of "Er" in the diagram?
Drupady [299]

Answer:

The significance of "Er" in the diagram is :

B.) Threshold energy for reaction

Explanation:

Threshold energy : It is total amount of energy required by the reactant molecule to reach the transition state .

Activation energy : It is the excess energy absorbed by the molecules to reach the transition state.

<u>Activation Energy = Threshold Energy - Average Kinetic Energy</u>

<u>This means Activation energy decreases on increasing kinetic energy</u>

On increasing Temperature average kinetic energy of the molecule increases which reduces the activation energy and the reaction occur faster in that case.

Catalyst also reduces the Activation energy.

<u>Er = Threshshold energy for reaction at 30 degree</u>

<u>Ea = Activation Energy</u>

<u>The given figure shows that the threshold energy decreases on increasing the temperature</u>

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more reliable. The more results the better results you get.

Explanation:

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AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

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According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

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