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Nimfa-mama [501]
3 years ago
11

While jogging, a 70.0-kg student generates thermal energy at a rate of 1200 W. To maintain a constant body temperature of 37.0∘C

, this energy must be removed by perspiration or other mechanisms. If these mechanisms failed and the heat could not flow out of the student's body, irreversible body damage could occur. Protein structures in the body are irreversibly damaged if body temperature rises to 44.0∘C or above. The specific heat of a typical human body is 3480J/(kg⋅K), slightly less than that of water. (The difference is due to the presence of protein, fat, and minerals, which have lower specific heat capacities.)
Physics
1 answer:
xxMikexx [17]3 years ago
5 0

Answer:

1421 seconds or 23.67 minutes

Explanation:

Q = Heat = 1200 W

c = Specific heat of human body = 3480 J/kgK

\Delta T = Change in temperature = (44-37)°C

t = Time taken

Q=\dfrac{mc\Delta T}{t}\\\Rightarrow t=\dfrac{mc\Delta T}{Q}\\\Rightarrow t=\dfrac{70\times 3480\times (44-37)}{1200}\\\Rightarrow t=1421\ s

The time student jogs before irreversible body damage occurs is 1421 seconds or 23.67 minutes

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