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aleksley [76]
3 years ago
5

Electromagnetic radiation behaves both as particles (called photons) and as waves. Wavelength (λ) and frequency (ν) are related

according to the equation c=λ×ν where c is the speed of light (3.00×108 m/s). The energy (E in joules) contained in one quantum of electromagnetic radiation is described by the equation E=h×ν where h is Planck's constant (6.626×10−34 J⋅s). Note that frequency has units of inverse seconds (s−1), which are more commonly expressed as hertz (Hz). A microwave oven operates at 2.20 GHz . What is the wavelength of the radiation produced by this appliance?
Physics
1 answer:
inessss [21]3 years ago
8 0
<h2>Answer: 136.363 m</h2>

Explanation:

We can find the wavelength of the radiation produced by the microwave oven by using the following given equation:

c=\lambda.\nu   (1)

Clearing \lambda :

\lambda=\frac{c}{\nu}   (2)

Knowing \nu=2.20 GHz=2.20(10)^{6}Hz=2.20(10)^{6}s^{-1}

\lambda=\frac{3(10)^{8}m/s}{2.20(10)^{6}s^{-1}}   (3)

\lambda=136.363m This is the wavelength of the radiation produced by the microwave

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If the period of a spring is 5 seconds what is the frequency
Scilla [17]

Answer:

C. 0.2 Hertz

Explanation:

The frequency of a spring is equal to the reciprocal of the period:

f=\frac{1}{T}

where

f is the frequency

T is the period

For the spring in this problem,

T = 5 s

therefore, the frequency is

f=\frac{1}{5 s}=0.2 Hz

7 0
4 years ago
What is the charge on an object that has 1.09x10^13 excess electrons?
Nadya [2.5K]

Answer:

-1.74\cdot 10^{-6} C

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

e=-1.6\cdot 10^{-19}C

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

Q=Ne

In this problem, the number of excess electrons in the object is:

N=1.09\cdot 10^{13}

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C

5 0
4 years ago
A 68.2 kg base runner begins his slide into second base while moving at a speed of 4.33 m/s. He slides so that his speed is zero
qwelly [4]

Answer:

147.653J = W_f

Explanation:

We know that:

E_i - E_f = W_f

where E_i is the initial energy, E_f is the final energy and W_f is the energy lost due to friction.

so:

\frac{1}{2}MV^2-0 = W_f

Where M is the mass and V is the velocity of the runner, so:

\frac{1}{2}(68.2kg)(4.33m/s)^2 = W_f

147.653J = W_f

7 0
4 years ago
Where is a good place to check your pulse?
jeyben [28]

Answer:

a

a

a

a

a

a

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a

a

a

a

a

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a

a

a

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6 0
3 years ago
Read 2 more answers
In a Young's double-slit experiment, a set of parallel slits with a separation of 0.114 mm is illuminated by light having a wave
elena-14-01-66 [18.8K]

Answer:

a) 2232nm

b) 2511nm

Explanation:

a) To find the path difference Δl you use the following formula:

\Delta l=m\lambda

m: order of a bright fringe

λ: wavelength of light = 558nm

for m=4:

\Delta l=(4)(558nm)=2232nm

b) The path difference for the case of destructive interference you have:

\Delta l=(m+\frac{1}{2})\lambda

m: order of a dark fringe

for m=4:

\Delta l=(4+\frac{1}{2})(558nm)=2511nm

7 0
3 years ago
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