Answer:
0.24 kg used up
Explanation:
He has a mass of 67 kg
The gravitational constant is 9.81 m/s^2
The distance upward is 3500 m
W = m*g*h
W = 67 * 9.81 * 3500
Work = 2,300,445 Joules
Work = 2300 kj
work = 2.30 * 10^6 joules in scientific notation.
Part B
He needs 4 times this amount to climb the mountain because the body is only 25% efficient in converting energy.
4*2.30 * 10^6 = 9.20 * 10^6 Joules of energy are therefore required.
The total amount in a kg of fat = 3.8 * 10^7 joules
x kg of fat is needed to provide 9.20.*10^6 joules
1 kg / (3.8 * 10^7 J ) = x kg / (9.20 * 10^6 J)
9.20 * 10 ^6 * 1 = 3.8 * 10^7 *x
9.20 * 10 ^6 / 3.8 * 10^7 = x
x = 0.24 kg of fat are needed
There are several approaches. The most favourable one (in my opinion) is this one:
1. Asking a question
2. Doing a research (how to answer this question)
3. Creating a hypothesis (NOT a thesis!)
4. Experimenting (to prove the hypothesis)
5. Analysing results from the experiment
6. Writing a thesis
It is called condensation
Answer:
1185 N
Explanation:
From Newton’s second law of motion,
F=ma where m= mass of motorcycle, a is acceleration of the motorcycle and F=Force
Net force acting on motorcycle
is given by
Where F is force acting on motorcycle and f is frictional force
Substituting F-f for
hence ma= F- f Substituting a with 3, m with 245Kg and f with 450N as provided
245*3= F- 450
F=245*3 +450= 1185 N
Answer:
= 8.33 Watt
Explanation:

where,
p = resistivity
l = length
A = cross section area
Given that ,
p = resistivity = 6.0 × 10–8 Ω
l = 2m
A = cross section area = 2.0 mm × 2.0 mm = 4 x 10^-6 m^2
A = 2 x 2 mm^2 = 4 x 10^-6 m^2
p = 6 x 10^-8 ohm metre,
V = 0.5 V
Let R be the resistance of the rod

R = 3 × 10⁻²Ω
Heat generated = V^2 / R
= (0.5)^2 / (3 x 10^-2)
= 8.33 Watt