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aleksley [76]
3 years ago
5

Electromagnetic radiation behaves both as particles (called photons) and as waves. Wavelength (λ) and frequency (ν) are related

according to the equation c=λ×ν where c is the speed of light (3.00×108 m/s). The energy (E in joules) contained in one quantum of electromagnetic radiation is described by the equation E=h×ν where h is Planck's constant (6.626×10−34 J⋅s). Note that frequency has units of inverse seconds (s−1), which are more commonly expressed as hertz (Hz). A microwave oven operates at 2.20 GHz . What is the wavelength of the radiation produced by this appliance?
Physics
1 answer:
inessss [21]3 years ago
8 0
<h2>Answer: 136.363 m</h2>

Explanation:

We can find the wavelength of the radiation produced by the microwave oven by using the following given equation:

c=\lambda.\nu   (1)

Clearing \lambda :

\lambda=\frac{c}{\nu}   (2)

Knowing \nu=2.20 GHz=2.20(10)^{6}Hz=2.20(10)^{6}s^{-1}

\lambda=\frac{3(10)^{8}m/s}{2.20(10)^{6}s^{-1}}   (3)

\lambda=136.363m This is the wavelength of the radiation produced by the microwave

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2 years ago
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Is the ratio between the sine of an angle of incidence to the sine of an angle of refraction is called the refractive index?
motikmotik

Answer:

Yes

Explanation:

Yes it is called the refractive index denoted by n

n=sin<i/sin<r

6 0
3 years ago
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Determine the resultant moment of the forces acting about the x, y, and z axes. Suppose that f1 = 200 n, f2 = 60 n, f3 = 115 n,
SpyIntel [72]

Based on the forces acting on the axes, the resultant moments will be (345, 400, 600 N·m)

<h3>What would be resultant moment about x-axis?</h3>

= F₃ x 3

= -115 x 3

= -345 N·m

<h3>What would be resultant moment about y-axis?</h3>

= F₁ x 2

= -200 x 2

= -400 N·m

<h3>What would be the resultant moment about z-axis?</h3>

= F₄ x 2

= -300 x 2

= - 600 N·m

In conclusion, the resultant moment about x, y, and z axes is (345, 400, 600 N·m)

Find out more on resultant moments at brainly.com/question/6278006.

5 0
2 years ago
Which is not expecting acceleration?
Elena L [17]

#1

A point on the outside of a spinning top whose rotational speed is constant.

Since the point at the top is at rest so it will not accelerate at all

A skydiver whose air resistance is equal to that of her weight.

Since weight is counter balanced by air resistance so net force on it is zero so acceleration will be zero

A car on the freeway experiencing a net force of -120 N.

Since net force is not zero so it will accelerate here

A submerged beach ball whose buoyant force is eight times the force of gravity on it.

Since buoyant force is more than the weight so it will not at rest and move upwards with some acceleration


#2

A frictionless spinning merry go round.

Since spinning wheel accelerating due to centripetal force so it is non inertial frame

A falling rock.

Falling rock is accelerating due to gravity so it is again non inertial frame

A hot air balloon moving at 30 degrees east of north with no net force.

since hot air balloon is having no force on it so its acceleration is zero and its an inertial frame

A space shuttle whose boosters just ignited for takeoff.

Since space shuttle is accelerating due to boosters so it is non inertial frame

#3

Here net force on it is due to two given forces

F_1 = 4320 N towards right

F_2 = 4380 N towards left

so here net force is given as

F = F_2 - F_1

F = 4380 - 4320 = 60 N

since force towards left is more so the direction will be towards left

so correct answer is 60 N towards left

4 0
3 years ago
A gun has a muzzle speed of 90 meters per second. What angle of elevation should be used to hit an object 150 meters away? Negle
Artist 52 [7]

Answer:

θ₀ = 84.78° (OR) 5.22°

Explanation:

This situation can be treated as projectile motion. The parameters of this projectile motion are:

R = Range of Projectile = 150 m

V₀ = Launch Speed of Projectile = 90 m/s

g = 9.8 m/s²

θ₀ = Launch angle (OR) Angle of Elevation = ?

The formula for range of a projectile is given as:

R = V₀² Sin 2θ₀/g

Sin 2θ₀ = Rg/V₀²

Sin 2θ₀ = (150 m)(9.8 m/s²)/(90 m/s)²

2θ₀ = Sin⁻¹ (0.18)

θ₀ = 10.45°/2

<u>θ₀ = 5.22°</u>

Also, we know that for the same launch velocity the range will be same for complementary angles. Therefore, another possible value of angle is:

θ₀ = 90° - 5.22°

<u>θ₀ = 84.78°</u>

7 0
3 years ago
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