Answer:
Explanation:
Given data
Length L=2.5 m
Radius R=d/2=30/2 = 15 mm
Torque based on allowable stress
Allowable shear stress τ=50 Mpa
Allowable torque T=(π/2)τc³
Torque based on allowable angle of twist
Allowable Angle of twist
Ф=7.5°
Ф=7.5×(π/180)=130.90×10⁻³ rad
Allowable torque
T=(GJФ)/L
T=(G(π/2)c⁴)Ф)/L
T=(πGc⁴Ф)/2
Maximum Power Transmitted
Maximum power transmitted is given by
To solve this problem, we will define speed as the amount of distance traveled per unit of time. We will clear the value of time and in parallel we will convert the Units to an international system to facilitate the calculation since we know the speed of light in a vacuum. The speed defined in terms of distance and time would be
The speed of light in a vacuum is and 1ft is equivalent to , so the estimated time would be
We know that 1 second is equivalent to , therefore
Therefore the time is 1.02ns
Answer:
The forces experienced by the middle particle are attractive, and the net force will remain the same (0) if and only if the distances of the sides particles to the middle particle are the same.
Explanation:
In example 20.3 the forces experienced by the middle particle are repulsive because all the particles are positive, for the case in which the particles on the sides are replaced for negative charge particles the forces experienced by the middle particle are attractive. Regarding the net force, because we don't know the distances we can not give a definitive answer, what we can say is that if the distances from the middle particle to the sides particles are the same the net force is zero for both cases (remain unchanged).