3 years ago

Computer science Need answers please ^^

Physics

1 answer:

shtirl [24]3 years ago

8 0

the cpu tells the ram what to do and the ram dose it tm pritty shure

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A diver running 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.0 s later reaches the water below. how hi

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<u>Answer:</u>

a) Height of cliff = 44.145 meter

b) 7.5 meter far from its base the diver hit the water.

<u>Explanation:</u>

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

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Initial velocity = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate displacement when time is 3 seconds.

$s= ut+\frac{1}{2} at^2\\ \\ =0*3+\frac{1}{2} *9.81*3^2\\ \\ =44.145meter$

So height of cliff = 44.145 meter.

b) Diver's horizontal motion:

Initial velocity = 2.5 m/s, acceleration = 0 $m/s^2$ , we need to calculate displacement when time is 3 seconds.

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3 years ago

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$2.59\times 10^{13}\ m$

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1 day = 24 hours

1 day = 24 × 3600 seconds

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Now, using the formula of speed to find the distance covered as follows :

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Putting all the values, we get :

$d=3\times 10^8\ m/s\times 86400\ s\\\\d=2.59\times 10^{13}\ m$

Hence, light will cover $2.59\times 10^{13}\ m$ of distance in one day.

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