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2 years ago

How does recycling wood products help maintain the supply of forestland for a longer period of time?

Chemistry

1 answer:

LiRa [457]2 years ago

3 0

Recycling reduces the demand for new wood is correct

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Name Formula: Lead (II) Oxide F) Pb2O G) PbO2 H) PbO I) Pb2O2

garik1379 [7]

Answer:

PbO is the Answer

Explanation:

4 0

2 years ago

There is nothing that you can do to conserve energy. True or False

Firdavs [7]

I am going to say it is false.

6 0

3 years ago

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Which of the following is not a property of an acid?

SpyIntel [72]

Answer:

1. bitter

2. turns litmus paper red

3. oxygen, hydrogen, and molecules.

Explanation:

7 0

3 years ago

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Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?

german

Answer : The correct option is, (A) $AlCl_3$

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) $AlCl_3$

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of $AlCl_3$ will be,

$AlCl_3\rightarrow Al^{3+}+3Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Al^{3+}+3Cl^{-}$ = 1 + 3 = 4

(B) $KI$

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of $KI$ will be,

$KI\rightarrow K^{+}+I^{-}$

So, Van't Hoff factor = Number of solute particles = $K^{+}+I^{-}$ = 1 + 1 = 2

(C) $CaCl_2$

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of $CaCl_2$ will be,

$CaCl_2\rightarrow Ca^{2+}+2Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Ca^{2+}+2Cl^{-}$ = 1 + 2 = 3

(D) $MgSO_4$

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of $MgSO_4$ will be,

$MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}$

So, Van't Hoff factor = Number of solute particles = $Mg^{2+}+SO_4^{2-}$ = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, $AlCl_3$

7 0

2 years ago

A mixture of three noble gases has a total pressure of 1.25 atm. The individual pressures exerted by neon and argon are 0.68

FinnZ [79.3K]

First of all, as you seen the gases are noble which means that will not react with each other and in this case each gas create individual pressure.

P $_{T}$ = total pressure

P $_{Ne}$ = pressure of neon

P $_{Ar}$ = pressure of argon

P $_{He}$ = pressure of helium {which is required}

P $_{T}$ = P $_{Ne}$ + P $_{Ar}$ + P $_{He}$

1.25 = 0.68 + 0.35 + P $_{He}$

P $_{He}$ = 1.25 - [0.68 + 0.35] = 0.22 atm

4 0

2 years ago