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neonofarm [45]
3 years ago
14

What is the net displacement of the particle between 0 seconds and 80seconds?

Physics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

Option (A)

Explanation:

Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).

Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB

Area of triangle AOB = \frac{1}{2}(\text{Base})(\text{height})

                                   = \frac{1}{2}(40)(4)

                                   = 80 m

Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD

Area of ΔBCD = \frac{1}{2}(40)(4)

                        = 80 m

Total displacement of the particle from t = 0 to t = 80 seconds,

= 80 + 80

= 160 m

Option (A) will be the answer.

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A mass of 1 slug, when attached to a spring, stretches it 2 feet and then comes to rest in the equilibrium position. Starting at
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Answer:

Y=(\dfrac{3}{16}+t \dfrac{3}{8})e^{-2t}-\dfrac{3}{16}cos 4t

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Given that m= 1 slug and given that spring stretches by 2 feet so we can find the spring constant K

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We know that equation for spring mass system

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Now by putting the values

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To find the constant A and B we have to compare this equation with equation 1.

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1 (-16A cos 4t-16B sin 4t)+8( -4A sin 4t+4B cos 4t)+16(A cos 4t+ B sin 4t)=6sin4 t

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y=-3/16 cos 4t

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Homogeneous version of above equation

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So the general equation

Y=(C_1+tC_2)e^{-2t}-3/16 cos 4t

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C_1=\dfrac{3}{16}

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3 0
3 years ago
When Bella pushes a box with a mass of 5.25 kilograms with a force of 15.75 newtons, it accelerates at a rate of 2.5 meters/seco
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Now, watch:

The mass of the box is 5.25 kilograms, and the box is
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How much ?

            (Bella's 15.75 newtons) minus (13.125 that the box feels)

           =      2.625 newtons backwards, applied by friction.


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