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neonofarm [45]
3 years ago
14

What is the net displacement of the particle between 0 seconds and 80seconds?

Physics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

Option (A)

Explanation:

Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).

Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB

Area of triangle AOB = \frac{1}{2}(\text{Base})(\text{height})

                                   = \frac{1}{2}(40)(4)

                                   = 80 m

Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD

Area of ΔBCD = \frac{1}{2}(40)(4)

                        = 80 m

Total displacement of the particle from t = 0 to t = 80 seconds,

= 80 + 80

= 160 m

Option (A) will be the answer.

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Answer:

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Emily holds a banana of mass m over the edge of a bridge of height h. She drops the banana and it falls to the river below. Use
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Answer:

The mass of the banana is m and it is at height h.

Applying the Law of Conservation of Energy

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Here, total energy is the sum of kinetic energy and potential energy

K.E_{i} + P.E_{i} = K.E_{f} + P.E_{f}       (a)

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<em>cutting 'm' from both sides</em>

<em>                                           </em>gh = 1/2v^{2}

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8 0
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Answer:

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