What is the net displacement of the particle between 0 seconds and 80seconds?
1 answer:
Answer:
Option (A)
Explanation:
Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).
Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB
Area of triangle AOB =
=
= 80 m
Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD
Area of ΔBCD =
= 80 m
Total displacement of the particle from t = 0 to t = 80 seconds,
= 80 + 80
= 160 m
Option (A) will be the answer.
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Answer:
The electric field inside the wire will remain the same or constant, while the drift velocity will by a factor of four.
Explanation:
Electron mobility, μ =
where
= Drift velocity
E = Electric field
Given that the electric field strength = 1.48 V/m,
Therefore since the electric potential depends on the length of the wire and the attached potential difference, then when the electron mobility is increased 4 times the Electric field E will be the same but the drift velocity will increase four times. That is
4·μ =