Question

What is the net displacement of the particle between 0 seconds and 80seconds?

Answer 1

Answer:

Option (A)

Explanation:

Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).

Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB

Area of triangle AOB = $\frac{1}{2}(\text{Base})(\text{height})$

                                   = $\frac{1}{2}(40)(4)$

                                   = 80 m

Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD

Area of ΔBCD = $\frac{1}{2}(40)(4)$

                        = 80 m

Total displacement of the particle from t = 0 to t = 80 seconds,

= 80 + 80

= 160 m

Option (A) will be the answer.