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2 years ago

How to do electronic configuration

1 answer:

5 0

A Bohr diagram of lithium. In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule (or other physical structure) in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s 2 2s 2 2p 6

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Integrated rate law for second order unimolecular irreversible

kirill115 [55]

Answer:

The rate law for second order unimolecular irreversible reaction is

$\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }$

Explanation:

A second order unimolecular irreversible reaction is

2A → B

Thus the rate of the reaction is

$v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}$

rearranging the ecuation

$-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}$

Integrating between times 0 to t and between the concentrations of $[A]_{0}$ to [A].

$\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}$

Solving the integral

$\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }$

5 0

3 years ago

For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

The reaction

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

Moles of nitrogen monoxide

Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) Maximun ammount of nitrogen gas => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

8 0

3 years ago

Can someone help me?

kupik [55]

Answer:

#1)2.23hrs

Explanation:

= 134/60

=2.23

=2.23hrs

4 0

2 years ago

The least polar bond is found in a molecule of hi hf hcl hbr

mario62 [17]

Answer:

HI is least polar

Explanation:

5 0

3 years ago

How many electrons would be found in the Ion who’s symbol is I-

Vesnalui [34]

Answer:

Explanation:

Given symbol of the element:

I⁻

Number of electrons found in an ion with the symbol:

This is a iodine ion:

For an atom of iodine:

Electrons = 53

Protons = 53

Neutrons = 74

An ion of iodine is one that has lost or gained electrons.

For this one, we have a negatively charged ion which implies that the number of electrons is 1 more than that of the protons.

So, number of electrons = 53 + 1 = 54

The number of electrons in this ion is 54

6 0

2 years ago