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4 years ago

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The potential difference between the plates of a parallel plate capacitor is 4.00 V. If the plate separation for this capacitor

is 6.00 cm, what is the intensity of the electric field between the plates of this capacitor?

1 answer:

shtirl [24]4 years ago

4 0

<h2>Answer:</h2>

66.67 V / m

<h2>Explanation:</h2>

The electric field intensity (E) between the plates of a capacitor is the ratio of the potential difference (V) between the plates to the distance (d) of separation between the plates. Electric field intensity can be measured in V/m. It can be written as follows;

E = V / d ----------------------------(i)

<em>From the question;</em>

V = 4.00V

d = 6.00cm = 0.06m

<em>Substitute these values into the equation above. i.e equation (i) as follows;</em>

E = 4.00 / 0.06

E = 66.67 V / m

Therefore, the electric field intensity between the plates of the capacitor is 66.67 V / m

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