When the marble is dropped from a certain height, its gravitational potential energy converts into kinetic energy. So the kinetic energy gained is equal to the variation of gravitational potential energy:

$\Delta U=mg\Delta h$

where

m is the mass of the marble

g = 9.8 m/s^2 is the acceleration of gravity

$\Delta h$ is the change in height

In this problem, we have

m = 50 g = 0.05 kg

$\Delta U = 100 J$

Solving the formula for $\Delta h$ , we find the necessary height from which the marble should be dropped:

$\Delta h = \frac{\Delta U}{mg}=\frac{100}{(0.05)(9.8)}=204 m$

7 0

3 years ago

A body of mass 1kg is made to oscillate on a spring of force constant 16 n/m calculate 1 the angular frequency 2 the frequency o

Scilla [17]

Explanation:

Given that,

Mass of a body, m = 1 kg

Force constant, k = 16 N/m

We need to find the angular frequency and the frequency of oscillation.

(a) The angular frequency of a body is given by :

$\omega=\sqrt{\dfrac{k}{m}} \\\\=\omega=\sqrt{\dfrac{16}{1}} \\\\=4\ rad/s$

(b) The frequency of oscillation is given by :

$f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{4}{2\pi}\\\\=\dfrac{2}{\pi}\ Hz$

Hence, this is the required solution.

7 0

3 years ago

Most of the compunds that make up organisms contain __

8090 [49]

All living creatures contain carbon

6 0

3 years ago

A 62 kg box is lifted 12 meters off the ground. How much work was done?

OleMash [197]

7291.2 I hope this is right

6 0

4 years ago

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