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Artemon [7]
3 years ago
11

The empirical formula of styrene is CH; find the % composition for H and CH. How many atoms are present in a 2.00 gram sample of

styrene?
PLEASE HELP! THANK YOU
Chemistry
1 answer:
lina2011 [118]3 years ago
8 0
% Composition = ?
no atom in 2 g of styrene =? 
molar mass of strene =104.15
% composition of c= 12/13.008 =.922*100=92.2
% composition of h =1.008/13.008=0.0774*100= 7.74

no gram atom=mass in kg /molar mass=2/104.15 =0.01920 mol
no of gram atom * avogadro's number  = 0.0192*6.02 *10( exponent 23) =1.15584 


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Answer: The volume of hydrogen gas produced will be, 12.4 L

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From the balanced reaction we conclude that

As, 3 mole of Mg react with 2 mole of H_3PO_4

So, 0.553 moles of Mg react with \frac{2}{3}\times 0.553=0.369 moles of H_3PO_4

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Now we have to calculate the moles of H_2

From the reaction, we conclude that

As, 3 mole of Mg react to give 3 mole of H_2

So, 0.553 mole of Mg react to give 0.553 mole of H_2

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As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies 0.553\times 22.4=12.4L volume of hydrogen gas

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