Answer 1) When a strong acid like

reacts with

usually the equilibrium shifts to the right because
As per the Le chatelier's principle "if in any reaction, a dynamic equilibrium is disturbed by changing the any of the conditions, the position of equilibrium moves to counteract the change." So, in the given reaction when

reacts with

it generates carbon dioxide and water as a by product, if we are adding

it will remove some of the

molecule from the reaction mixture, which then tends to shift the equilibrium towards right.
Answer 2) The same would be observed in this case, if we replace

with HCl it will shift the equilibrium to the right as their will be generation of AgCl as the precipitate.
As per the definition of Le Chatelier's principle if we add reactants in the reaction the equilibrium will tend to move towards right, also if we replace the products or remove it then too it will shift the equilibrium towards right. So, in this reaction you are removing

and

ions from the solution.
Answer:
Since KOH is a strong base, the solution completely ionizes into K+ and OH- when in water. The reaction KOH --> K+ + OH- takes place. The concentration of [ OH- ] can then be used to calculate the pOH of the solution. pH = 14 - pOH = 14 - 1.48 = 12.52
Explanation:
Answer:
Mass is the quantity of an object.
Weight is the force with which the object is attached towards the earth.
Hope it helps
Answer:
A
Explanation:
increase in energy - hotter and/or more reactive
decrease in energy - colder and/or less reactive
Since it is going from a liquid to solid it will have a tighter arrangement of particles.
First you need to find the mass of one mole of the element. (say Fe)
Find Fe on the periodic table, it should tell you what the average atomic mass is.
The average atomic mass = mass of one mole.(in this case it is 55.85g)
Take your moles (1.35mol Fe) and multiply it by the mass of one mole (55.85g)
1.35mol*55.85g/mol=75.39g
(Just repeat that method for the other problems) use the formula <span><span>moles=<span><span>mass</span><span>Molar mass
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