Two blocks of rubber with a modulus of rigidity G =10 MPa are bonded to rigid supports and to a plate AB. Knowing that b = 200 m
m and c = 125 mm, determine the largest allowable load P and the smallest allowable thickness a of the blocks if the shearing stress in the rubber is not to exceed 1.2 MPa and the deflection of the plate is to be at least 6 mm.
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Answer:
The value of Modulus of elasticity E = 85.33 ×
Beam deflection is = 0.15 in
Explanation:
Given data
width = 5 in
Length = 60 in
Mass of the person = 125 lb
Load = 125 × 32 = 4000
We know that moment of inertia is given as
I = 1.40625
Deflection = 0.15 in
We know that deflection of the beam in this case is given as
Δ =
E = 85.33 ×
This is the value of Modulus of elasticity.
Beam deflection is = 0.15 in