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krok68 [10]
3 years ago
8

Two blocks of rubber with a modulus of rigidity G =10 MPa are bonded to rigid supports and to a plate AB. Knowing that b = 200 m

m and c = 125 mm, determine the largest allowable load P and the smallest allowable thickness a of the blocks if the shearing stress in the rubber is not to exceed 1.2 MPa and the deflection of the plate is to be at least 6 mm.

Engineering
1 answer:
g100num [7]3 years ago
5 0

Answer:

Solution is given in the attachments.

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Cite the phases that are present and the phase compositions for the following alloys: (a) 15 wt% Sn - 85 wt% Pb at 100 o C. (b)
Novosadov [1.4K]

Answer:

a)  ∝  and β

   The phase compositions are :

    C_{\alpha } = 5wt% Sn - 95 wt% Pb

    C_{\beta } =  98 wt% Sn - 2wt% Pb

b)

The phase is; ∝  

The phase compositions is;   82 wt% Sn - 91.8 wt% Pb

Explanation:

a) 15 wt% Sn - 85 wt% Pb at 100⁰C.

The phases are ; ∝  and β

The phase compositions are :

C_{\alpha } = 5wt% Sn - 95 wt% Pb

C_{\beta } =  98 wt% Sn - 2wt% Pb

b) 1.25 kg of Sn and 14 kg Pb at 200⁰C

The phase is ; ∝  

The phase compositions is;  82 wt% Sn - 91.8 wt% Pb

Csn = 1.25 * 100 / 1.25 + 14 = 8.2 wt%

Cpb = 14 * 100 / 1.25 + 14 = 91.8 wt%

6 0
3 years ago
Which of the following is true about modern hydraulic lifts?
kaheart [24]

The modern hydraulic lifts make use of biodegradable fluid to transmit hydraulic power

<em>Question: The options are left out in the question. The details and facts about the modern hydraulic lift are presented here</em>

<em />

Details about the modern hydraulic lifts include;

The development of the  modern hydraulic occurred in the Industrial Revolution to perform task done previously by steam powered elevators  

The power of the hydraulic lift come from the hydraulic cylinder known as the actuator, which in turn is powered by pressurized hydraulic fluid such as oil

The hydraulic fluid is pushed by a piston rod through which energy is capable of being transferred, such that the applied force is multiplied, to provide more power for lifting

<u>Facts about the modern hydraulic lifts include;</u>

  • The dry motor in the modern hydraulic lift is more efficient and consumes 20% less energy
  • It comprises of valves that are controlled electronically such that the response is much rapid and the energy consumption is reduced by a further 20%
  • The cars used in the modern lift are lighter, as well as the slings, which reduces the power usage by 20%
  • It makes use of chemicals which are environmentally friendly as hydraulic fluid
  • The flash point of the fluid used is higher, as well as it posses 50% lower compressibility as well elasticity

Learn more here:

brainly.com/question/16942803

6 0
2 years ago
Given a 12-bit A/D converter operating over a voltage range from ????5 V to 5 V, how much does the input voltage have to change,
Doss [256]

Answer:

2.44 mV

Explanation:

This question has to be one of analog quantization size questions and as such, we use the formula

Q = (V₂ - V₁) / 2^n

Where

n = 12

V₂ = higher voltage, 5 V

V₁ = lower voltage, -5 V

Q = is the change in voltage were looking for

On applying the formula and substitutiting the values we have

Q = (5 - -5) / 2^12

Q = 10 / 4096

Q = 0.00244 V, or we say, 2.44 mV

6 0
3 years ago
If a resistor only has three color bands, it has a tolerance of 20 percent. What would this mean for a resistor specified at 10,
Norma-Jean [14]
B is the correct answe it will fail if more than 12.000
Hope this helps
:)
3 0
2 years ago
Block A hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.
nikitadnepr [17]

Answer:

a)  m_e= 3.05 Kg

b)  \rho=1072.3kg/m^3

c)  m_e= 3.05 Kg

Explanation:

From the question we are told that:

Beaker Mass m_b=1.20

Liquid Mass m_l=1.85

Balance D:

Mass m_d=3.10

Balance E:

Mass m_e=7.50

Volume v=4.15*10^{-3}m^3

a)

Generally the equation for Liquid's density is mathematically given by

m_e=m_b+m_l+(\rho*v)

\rho=\frac{7.50-(1.2+1.85)}{4.15*10^{-3}}

\rho=1072.3kg/m^3

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

m_d=m- (\rho *v )

m=3.10+ (1072.30 *4.15*10^{-3}m^3 )

m=18.10kg

c)

Generally the equation for E's Reading at A pulled is mathematically given by

m_e=m_b+m_l

m_e = 1.20 + 1.85

m_e= 3.05 Kg

6 0
3 years ago
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