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Dmitriy789 [7]
3 years ago
8

Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the en

tire structure would sink by a certain amount for every additional floor that is added. If the maximum permissible limit for depression of the structure is 20 centimeters, how many floors can be safely added to the building?
Physics
1 answer:
vovikov84 [41]3 years ago
8 0
Let's call this "certain amount" with a variable, x, (since it's not specified in the question, I will assume that the answer shall just be based on this variable).

So every additional floor will make the building sink by x, and let's make the unit cm, so x cm.

Now we know that the maximum depression is 20 cm, and it is also

x*y, where y is the number of floors.

So we have x*y=20,

therefore the number of floors is:
20/x or
\frac{20}{x}



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A capacitor charging circuit consists of a battery, an uncharged 20 μF capacitor, and a 6.0 kΩ resistor. At t = 0 s the switch i
aliya0001 [1]

Answer:

Battery voltage will be equal to 9.65 volt

Explanation:

We have given capacitance C=20\mu F=20\times 10^{-6}F

Resistance R=6kohm=6000ohm

Time constant of RC circuit is

\tau =RC=20\times 10^{-6}\times 6000=0.12sec

Time is given t = 0.15 sec

Current i = 0.46 mA

Current in RC circuit is given by

i=\frac{V}{R}e^{\frac{-t}{\tau }}

0.00046=\frac{V}{6000}e^{\frac{-0.15}{0.12 }}

0.00046=\frac{V}{6000}\times 0.286

V = 9.65 volt

So battery emf will be equal to 9.65 volt

5 0
3 years ago
A positively charged particle of mass 7.2 x 10-8 kg is traveling due east with a speed of 88 m/s and enters a 0.6-T uniform magn
Marianna [84]

Answer:

q = 8.57 10⁻⁵ mC

Explanation:

For this exercise let's use Newton's second law

         F = ma

where force is magnetic force

        F = q v x B

the bold are vectors, if we write the module of this expression we have

         F = qv B sin θ

as the particle moves perpendicular to the field, the angle is θ= 90º

        F = q vB

the acceleration of the particle is centripetal

        a = v² / r

we substitute

        qvB = m v² / r

         qBr = m v

          q =\frac{m\  v}{B\  r}

The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use

          v = d / t

the distance is ¼ of the circle,

          d = \frac{1}{4} \  2\pi  r

           d =\frac{\pi }{2r}

we substitute

           v =  \frac{\pi  r}{2t}

           r = \frac{2 \ t  \ v}{\pi }

           

let's calculate

           r =\frac{2 \ 2.2  \ 10^{-3} \ 88}{\pi } 2 2.2 10-3 88 /πpi

           r = 123.25 m

         

let's substitute the values

           q = \frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}7.2 10-8 88 / 0.6 123.25

            q = 8.57 10⁻⁸ C

Let's reduce to mC

           q = 8.57 10⁻⁸ C (10³ mC / 1C)

           q = 8.57 10⁻⁵ mC

4 0
3 years ago
Which of the following statements is true?
Lilit [14]

A. All natural radiation is at a level low enough to be safe

8 0
3 years ago
Is velocity a scalar or a vector
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Velocity<span> is a</span>vector<span> quantity; it is direction-aware.</span>
5 0
3 years ago
Read 2 more answers
A firecracker in a coconut blows the coconut into three pieces. Two pieces of equal mass fly off south and west, perpendicular t
Natasha_Volkova [10]

Answer:

v=12.5 i + 12.5 j m/s

Explanation:

Given that

m₁=m₂ = m

m₃ = 2 m

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u₂ =- 25 i m/s

Lets take the speed of the third mass = v m/s

From linear momentum conservation

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0 = -25 j m  - 25 i m + 2 m v

2 v=25 j   + 25 i m/s

v=12.5 i + 12.5 j m/s

Therefore the speed of the third mass will be v=12.5 i + 12.5 j m/s

4 0
3 years ago
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