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3 years ago

12

What are the values for % Cl and % F, respectively, for Sample II?

1 answer:

horsena [70]3 years ago

6 0

Answer:

Explanation:

The mass percentages of chlorine and fluorine:

Given:

Mass of chlorine = 5.753g

Mass of fluorine = 9.248g

Find the total of the masses given:

Total mass = mass of chlorine + mass of fluorine = 5.753 + 9.248 = 15.001g

% of Cl = $\frac{mass of chlorine}{total mass}$ x 100

% of Cl = $\frac{5.753}{15.001}$ x 100 = 38.35%

% of F = $\frac{mass of fluorine}{total mass}$ x 100

% of F = $\frac{9.248}{15.001}$ x 100 = 61.65%

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(Thermodynamics)

frutty [35]

Answer:

3853 g

Step-by-step explanation:

M_r: 107.87

16Ag + S₈ ⟶ 8Ag₂S; ΔH°f = -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat

3 0

2 years ago

Fred mixes a solution using two types of solutions: 0.60 liters containing 10% alcohol and 0.40 liters containing 35% alcohol. W

insens350 [35]

The alcohol concentration of the mixed solution is 20%

Simplification :

Based on the given condition, formulate :

35% ×0.40 + 0.6 ×10% ÷{ 0.4+0.6}

Calculate the product : $\frac{0.14+0.06}{0.4 + 0.6}$

Calculate the sum or difference : $\frac{0.2}{1}$

Any fraction with denominator 1 is equal to numerator : 0.2

Multiply a number to both numerator, denominator : 0.2 × $\frac{100}{100}$

Calculate the product or quotient : $\frac{20}{100}$

A fraction with denominator equals to 100 to a percentage 20%.

How do you find the concentration of a mixed solution?

In general when your are mixing two different concentrations together first calculate number of moles for each solution (n=CV ,V-in liter) then add them together it will be total moles,then concentration of mixture will be = total moles / total volume(liter).

Learn more about concentration of alcohol :

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5 0

1 year ago

Complete and balance the chemical equations for the precipitation reactions, if any, between the following pairs of reactants, a

Crank

Explanation:

a. $Pb(NO_3)_2(aq) + Na_2SO_4(aq)$ → ?

$Pb(NO_3)_2(aq) + Na_2SO_4(aq)\rightarrow PbSO_4(s)+2NaNO_3(aq)$

$Pb(NO_3)_2(aq)\rightarrow Pb^{2+}(aq)+2NO_3^{-}(aq)$

$Na_2SO_4(aq)\rightarrow 2Na^++SO_4^{2-}(aq)$

$Pb^{2+}(aq)+2NO_3^{-}(aq)+2Na^++SO_4^{2-}(aq)\rightarrow PbSO_4(s)+2Na^++2NO_3^{-}(aq)$

Removing common ions from both sides, we get the net ionic equation:

$Pb^{2+}(aq)+SO_4^{2-}(aq)\rightarrow PbSO_4(s)$

b. $NiCl_2(aq) + NH_4NO_3(aq)$ →

$NiCl_2(aq) + NH4NO_3(aq) \rightarrow Ni(NO_3)_2+NH_4Cl(aq)$

No precipitation is occuring.

c. $Fe_Cl2(aq) + Na_2S(aq)$ →

$FeCl_2(aq) + Na_2S(aq)\rightarrow FeS(s)+2NaCl(aq)$

$FeCl_2(aq)\rightarrow Fe^{2+}(aq)+2Cl^{-}(aq)$

$Na_2S(aq)\rightarrow 2Na^++S{2-}(aq)$

$Fe^{2+}(aq)+2Cl^{-}(aq)+2Na^++S^{2-}(aq)\rightarrow FeS(s)+2Na^++2Cl^{-}(aq)$

Removing common ions from both sides, we get the net ionic equation:

$Fe^{2+}(aq)+S^{2-}(aq)\rightarrow FeS(s)$

d. $MgSO_4(aq) + BaCl_2(aq)$ →

$MgSO4(aq) + BaCl2(aq)\rightarrow BaSO_4(s)+MgCl_2$

$MgSO_4(aq)\rightarrow Mg^{2+}(aq)+SO_4^{2-}(aq)$

$BaCl_2(aq)\rightarrow Ba^{2+}+2Cl^{-}(aq)$

$Mg^{2+}(aq)+SO_4^{2-}(aq)+Ba^{2+}+2Cl^{-}(aq)(aq)\rightarrow BaSO_4(s)+Mg^{2+}(aq)+2Cl^{-}(aq)$

Removing common ions from both sides, we get the net ionic equation:

$Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

5 0

2 years ago

At the equilibrium point in the decomposition of phosphorus pentachloride to chlorine and phosphorus trichloride, the following

Hitman42 [59]

Answer: $K_{eq}$ for the reaction is 5.55

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

At eqm. conc. (0.010) M (0.15) M (0.37) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(0.37)\times (0.15)}{(0.010)}$

$K_c=5.55$

Thus the $K_{eq}$ for the reaction is 5.55

5 0

2 years ago

Which unit represents 100 meters?

adell [148]

Answer:

Hectometer.

Explanation:

<u><em>Hecto- means 100; a hectometer is 100 meters.</em></u>

6 0

2 years ago

Read 2 more answers