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3 years ago

How far is my house if I travel 1 mi/min and it takes me 23 minutes to go home

Chemistry

1 answer:

Musya8 [376]3 years ago

4 0

Answer: The answer would be 23 miles

Explanation: If you are traveling 1mi/min for 23 mins you would add 1, 23 times because it is 1 mile PER minute. Therefore it would be 23 miles.

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GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect nor

Shkiper50 [21]

Answer:

0.87 pg

Explanation:

GenAlex Medical, a leading manufacturer of medical laboratory equipment, is designing a new automated system that can detect normal levels of dissolved triiodothyronine (230. to 660 pg/dL), using a blood sample that is as small as 380 μL. Calculate the minimum mass in picograms of triiodothyronine that the new system must be able to detect. Be sure your answer has the correct number of significant digits.

Step 1: Convert 380 μL to deciliters

We will use the following conversion factors.

1 L = 10⁶ μL

1 L = 10 dL

380 μL × 1 L/10⁶ μL × 10 dL/1 L = 3.8 × 10⁻³ L

Step 2: Calculate the minimum mass of triiodothyronine that can be found in a 3.8 × 10⁻³ L blood sample

Since we are looking for the minimum mass, we will use the lower limit of the concentration interval (230. pg/dL).

3.8 × 10⁻³ L × 230. pg/dL = 0.87 pg

7 0

3 years ago

PLZ HELP (SCIENCE) Match the following items.

FromTheMoon [43]

Oxidation: a chemical change resulting form a reaction with oxygen
Endothermic:a reaction that takes in energy
Exothermic: a reaction that releases energy
Decomposition:chemical change whereby a molecule breaks down into simpler moles clues or elements
Subscript:written underneath or below

6 0

2 years ago

Read 2 more answers

What concentrations of acetic acid (pKa = 4.76) and acetate would be required to prepare a 0.15 M buffer solution at pH 5.0? Not

Leni [432]

Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

pH = pka + log₁₀ [A⁻]/[HA] -Where A⁻ is acetate ion and HA is acetic acid-

Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

1,7378 = [A⁻]/[HA] (1)

As concentration of buffer is 0,15M, it is possible to write:

[A⁻] + [HA] = 0,15M (2)

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need acetic acid 0,055M and acetate 0,095M to obtain the buffer you need.

i hope it helps!

7 0

3 years ago

Suppose you are a food chemist working for a company that makes and manufactures soda. Your job is to create a new soft drink wi

Mekhanik [1.2K]

Answer:

The answer to your question is given after the questions so I just explain how to get it.

Explanation:

Get the molecular weight of Phosphoric acid

H₃PO₄ = (3 x 1) + (31 x 1) + (16 x 4)

= 3 + 31 + 64

= 98 g

98 g ----------------- 1 mol

0.045 g --------------- x

x = (0.045 x 1) / 98

x = 0.045 / 98

x = 0.00046 moles or 4.6 x 10 ⁻⁴

Molarity = $\frac{moles}{volume}$

Molarity = $\frac{0.00046}{0.35}$

Molarity = 0.0013 or 1.31 x 10⁻³

Formula C₁V₁ = C₂V₂

V₁ = C₂V₂ / C₁

Substitution

V₁ = (0.0013)(1) / 0.01

Simplification and result

V₁ = 0.0013 / 0.1

V₁ = 0.13 l = 130 ml

7 0

3 years ago

Given 6.98 x 10 4 power grams of iron, calculate the moles of iron present

KiRa [710]

Answer:

1249.88 mol.

Explanation:

∵ no. of moles of Fe = mass of Fe/atomic weight of Fe.

∴ no. of moles of Fe = (6.98 x 10⁴ g)/(55.845 g/mol) = 1249.88 mol.

6 0

3 years ago