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julsineya [31]
3 years ago
7

PLEASE HELP MEEEEE

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
8 0

Answer:

hey there! it gains an electron and has an octet in its inner shell it loses an electron and has an octet in the next lowest energy level it gains an electron and has an octet in the lowest energy level it gains an electron and has an octet in its outer shell

HAVE A GRET DAY! ;D

Explanation:

tbh idk if im 100% sure if im right but i hope i am :)

Shalnov [3]3 years ago
5 0

Answer:

The correct answer is <em>"It loses an electron and has an octet in the next-lowest energy level."</em>

Explanation:

Valencia electrons are the electrons found in the last electronic layer (called valence orbitals). These electrons are what determine the ability of the atom to form bonds. When an element joins another, it does so through its valence electrons. It is also possible to say that these electrons are the electrons furthest from the nucleus of the atom, which is why they participate in chemical reactions.

An ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

In the ionic bond, when the metallic atom has a single electron in its outer layer and the non-metallic one needs an electron to complete its layer; The metallic atom yields its electron to the nonmetal for both elements. Thus the ions comply with the octet rule and, therefore, are more stable. Remember that the octet rule states that the atom is stable when it presents in its valence layer 8 electrons. This configuration is similar to that of a noble gas, which are the elements located at the right end of the periodic table.

Potassium is a metal that is in group 1 and has an electron in its last layer (layer S). Then this electron and becomes a cation. In this way it acquires the stable configuration of the argon noble gas Ar, which is the closest noble gas in the periodic table.

So, <u><em>the correct answer is "It loses an electron and has an octet in the next-lowest energy level."</em></u>

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If a hydrogen atom has its electron in the n = 3 state, how much energy in ev is needed to ionize it?
tensa zangetsu [6.8K]

The energy of the hydrogen atom will be -0.85 ev.

Ionization, also known as ionization, would be the phenomenon by which an atom or molecule gains or loses electrons to acquire a negative and positive charge, frequently in conjunction with those other chemical changes. Ions are the name for the electrically charged molecular or atom that results.

These chemicals are known as ionic compounds, with table salt serving as an example. Ionization would be the process of removing electrons from such an element as well as a molecule as well as the dissociation of an ionic material, such as salt, itself into the individual ions in a solution like water.

The energy of hydrogen atom will be calculated by using the formula:

E_{n} = -13.6 ev / n^{2}

where, E_{n} = energy of nth level, n is the state.

It is given that, n = 3 .

Now put the value of n in above equation.

E_{4} = -13.6 ev / 4^{2}\\E_{4} = -13.6 ev  / 16\\E_{4} = -0.85 ev

Therefore, the energy of the hydrogen atom will be -0.85 ev.

To know more about energy

brainly.com/question/1932868

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4 0
1 year ago
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Explanation:

A non-electrolyte is defined as a solution which does not contain any ions and hence, it is unable to conduct electricity.

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Similarly, a compound that is insoluble in water will not dissociate into ions. Hence, this type of solution will not be able to conduct electricity.

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Answer;

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upon heating a copper sample will expand, leading to a lower density

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In other words; The temperature of a body is the average kinetic energy of the molecules present in it. Therefore; when heat is supplied ( or temperature is increased) the average kinetic energy increases which increases the volume and thus density decreases.

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