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PSYCHO15rus [73]
3 years ago
12

the s and p sublevels of an atom of an element in period 3 are filled with electrons. Which orbitals are filled in this atom?

Chemistry
2 answers:
7nadin3 [17]3 years ago
7 0
<span>s sublevel = s orbital p sublevel= p orbitals the level tells you which orbitals exactly,
so level 3,
sub level p = 3p orbitals </span>
Levart [38]3 years ago
3 0

Answer:

1s,2s,2p,3s,3p

Explanation:

If an element is in period 3, then it has three energy levels. For the 3s and 3p orbitals to be filled, then the inner orbitals must have been filled before. That is 1s, 2s,2p, are all previously filled with electrons before the valence shells, 3s and 3p are filled. Hence all together, the filled orbitals are; 1s,2s,2p,3s,3p.

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Which statement is true regarding carbonic acid (H 2CO 3)? If body fluids are too alkaline, carbonic acid is excreted through th
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Answer:

the correct option is : If body fluids are too acidic, carbonic acid is excreted through the respiratory system in the form of carbon dioxide and water.

Explanation:

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8 0
3 years ago
What is the charge on an ion that has an atomic number of 16 and contains 14e-?
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3 0
2 years ago
When fertilization occurs one half of the DNA comes from the __________
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Read 2 more answers
Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo
Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

E=\frac{Nhc}{\lambda}

E= energy  = 348kJ= 348000 J  (1kJ=1000J)

N = avogadro's number = 6.023\times 10^{23}

h = Planck's constant = 6.626\times 10^{-34}Js&#10;

c = speed of light = 3\times 10^8ms^{-1}

348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}

\lambda=3.44\times 10^{-7}m=344nm    1nm=10^{-9}m

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

5 0
3 years ago
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