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eduard
3 years ago
10

Help please fast + i dont want an answer from g**gle .

Physics
1 answer:
velikii [3]3 years ago
7 0
7) 6, i believe, (Cu) 1 atom+ (S) 1 atom+(0)4 atoms.
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What type of system uses a liquid to transmit a force
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It can be transmit in hydraulic machine, exerting a small cross-sectional area can lead to pressure being transmitted
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Please help, no links please! I dont understand stand this question and im going to cry
Vaselesa [24]

Answer:

I'm pretty sure its helium

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3 years ago
Read 2 more answers
A 2.964 kilogram truck strikes a fence at 7.00 meters/second and comes to
Makovka662 [10]

10.92N

Explanation:

Given parameters:

Mass of truck = 2.964kg

Velocity of truck = 7m/s

Time taken = 1.9s

Unknown:

Average force on the car = ?

Solution:

According to newton's third law of motion "action and reaction are equal and opposite".

The force with which the truck struck the fence is the same as the force the fence acted on the truck with but in another direction.

 From newton's second law:

      Force  = mass x acceleration

      We know that acceleration is the change in velocity with time;

   acceleration = \frac{change in velocity }{time }

   Force =  mass x  \frac{change in velocity }{time }

  Force = \frac{2.964 x 7}{1.9} = 10.92N

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

3 0
3 years ago
In the steady state 1.2 ✕ 1018 electrons per second enter bulb 1. There are 6.3 ✕ 1028 mobile electrons per cubic meter in tungs
bekas [8.4K]

Answer:

E=12.2V/m

Explanation:

To solve this problem we must address the concepts of drift velocity. A drift velocity is the average velocity attained by charged particles, such as electrons, in a material due to an electric field.

The equation is given by,

V=\frac{I}{nAq}

Where,

V= Drift Velocity

I= Flow of current

n= number of electrons

q = charge of electron

A = cross-section area.

For this problem we know that there is a rate of 1.8*10^{18} electrons per second, that is

\frac{I}{q} = 1.2*10^{18}

A= 1.3*10^{-8}m^2

n=6.3*10^{28} e/m^3

\omicron{O} = 1.2*10^{-4}(m/s)(N/c) Mobility

We can find the drift velocity replacing,

V = \frac{1.2*10^{18}}{(1.3*10^{-8})(6.3*10^{28})}

V= 1.465*10^-3m/s

The electric field is given by,

E= \frac{V}{\omicron{O}}

E=\frac{1.465*10^-3}{1.2*10^{-4}}

E=12.2V/m

7 0
4 years ago
The way light bounces off a minerals surface is described by the minerals?
Step2247 [10]
Luster I think is what you are looking for
6 0
3 years ago
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