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2 years ago

How do you delete a brainly question

Physics

1 answer:

Likurg_2 [28]2 years ago

3 0

Answer:

you can't

Explanation:

you can only comment on your question and add more details or can ask a moderator or administrator to remove your question with a reason

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A box sits on the back of a flatbed truck. If the coefficient of static friction between the box and the truck bed is μs = 0.400

slava [35]

Answer:

28,699m

Explanation:

The force to make the box move should be μs.N=μs.m.g=m.|a|

then,

|a|=μs.g

Being

μs coefficient of static friction,

N the force made by the truck on the box caused by the gravity force,

m the mass,

g the acceleration of gravity

and a the acceleration of the truck.

$x = v \times t + \frac{1}{2} \times a \times {t}^{2}$

as the truck is stopping, the acceleration is negative. then,

$x = v \times t - \frac{1}{2} \times |a| \times {t}^{2}$

$|a| = v \div t \\ t = v \div |a|$

$x = v \times (v \div |a| ) - \frac{1}{2} \times |a| \times {(v \div |a|)}^{2}$

$x = v \times (v \div μs.g ) - \frac{1}{2} \times |a| \times {(v \div μs.g)}^{2}$

$x = \frac{{v}^{2}}{μs \times g} - \frac{1}{2} \times \frac{{v}^{2}}{μs \times g} \\ x = \frac{1}{2} \times \frac{{v}^{2}}{μs \times g} \\ x = 0.5 \times \frac{{(15m/s) }^{2} }{0.4 \times 9.8m/ {s}^{2} } = 28.699m$

28,699m

7 0

2 years ago

“All dogs bark. Fido barks. Thus, Fido is a dog,” is an example of which of the following?

nalin [4]

Deductive reasoning?

4 0

2 years ago

I want to answer these questions about vectors

stellarik [79]

Answer:

the first one answer is no

4 0

3 years ago

Electromagnetism consists of what two processes?

kherson [118]

Answer: it’s A and B

Explanation: everyone else on this post was giving you the wrong answer.

5 0

3 years ago

Read 2 more answers

Is a force necessary to keep an object in motion?

weqwewe [10]

Well according to Newton’s first law of motion, a body will remain in the state of rest or linear motion provided that an *external force* has been applied. So no, a force doesn’t need to keep a body to remain in linear motion, because F=ma, during uniform linear motion velocity is constant, hence acceleration is zero, so F=0

5 0

2 years ago