I don't know the answer. Can I ask your help to answer that question? pls.
Answer:
Explanation:
A, D,E and B i think is the correct answers
Answer:
0.7561 g.
Explanation:
- The hydrogen than can be prepared from Al according to the balanced equation:
<em>2Al + 6HCl → 2AlCl₃ + 3H₂,</em>
It is clear that 2.0 moles of Al react with 6.0 mole of HCl to produce 2.0 moles of AlCl₃ and 3.0 mole of H₂.
- Firstly, we need to calculate the no. of moles of (6.8 g) of Al:
no. of moles of Al = mass/atomic mass = (6.8 g)/(26.98 g/mol) = 0.252 mol.
<em>Using cross multiplication:</em>
2.0 mol of Al produce → 3.0 mol of H₂, from stichiometry.
0.252 mol of Al need to react → ??? mol of H₂.
∴ the no. of moles of H₂ that can be prepared from 6.80 g of aluminum = (3.0 mol)(0.252 mol)/(2.0 mol) = 0.3781 mol.
- Now, we can get the mass of H₂ that can be prepared from 6.80 g of aluminum:
mass of H₂ = (no. of moles)(molar mass) = (0.3781 mol)(2.0 g/mol) = 0.7561 g.
When
Carboxylic Acid is treated with
Alcohols in the presence of
acid as a catalyst it produces corresponding
Esters. This reaction is called as
Esterification.
Also, this reaction is a reversible reaction and the ester formed can also hydrolyze to produce Carboxylic acid and Alcohol. This reverse reaction is called as
transesterification.
The formation of
Ethyl Acetate from
Acetic Acid and
Ethanol in the presence of acid is shown below,
ALL organic molecules have carbon.
Hope this helps :)