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Blababa [14]
3 years ago
9

●1. What is the density of 2.0 g of a substance that has a volume of 5.0 mL?

Chemistry
1 answer:
anygoal [31]3 years ago
7 0
Density  =  Mass / Volume 

Density  =  2.0g /  5.0ml

Density = 0.4 g/ml
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Which stament about energy is mostly correct
klasskru [66]
I would say C is the most correct. 
In D it depends on what water source you're using. Let's say it is a waterfall, then the source of the water (melting ice or a lake) may disappear in the future. 
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6 0
3 years ago
All molecules are made of similar type of atom true or false​
vichka [17]

Answer:

False

Explanation:

Not all molecules are compounds, since some molecules, such as oxygen gas (above image of molecule of-O2) or ozone (O3), consist only of one element or type of atom. Water is also a molecule because it is made from atoms that have been chemically combined.

6 0
2 years ago
Read 2 more answers
How many carbon atoms are there in .500 mol of CO2?
AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

6 0
3 years ago
Referring to the experiment in which the scientists studies how long it
pshichka [43]

Answer:

different sizes of the parachute

Explanation:

this is what is being changed throughout the experiment

4 0
3 years ago
A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200
34kurt

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

4 0
2 years ago
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