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Snezhnost [94]
3 years ago
9

A 1 liter solution contains 0.247 M nitrous acid and 0.329 M sodium nitrite. Addition of 0.271 moles of calcium hydroxide will:

(Assume that the volume does not change upon the addition of calcium hydroxide.)
a. Raise the pH slightly
b. Lower the pH slightly
c. Raise the pH by several units
d. Lower the pH by several units
e. Not change the pH
f. Exceed the buffer capacity
Chemistry
1 answer:
Inessa05 [86]3 years ago
4 0

Answer:

a. Raise the pH slightly

Explanation:

We know that

Pka of HNO2/KNO2 =3.39

Moles of HNO2 in the buffer=0.247 mol/L×1L=0.247 moles

Moles of NO2-=0.329mol/L×1L=0.329 moles

If 0.271 moles of Ca(OH)2 is added it will neutralise 0.136 moles of acid ,HNO2,remaining HNO2=0.247-0.136=0.111 moles

Moles of NO2- will increase as 0.0333 moles Ca(NO)2 will be formed =0.0333+0.036=0.0693 moles

pH=pka+log [base]/[acid]      {henderson -hasselbach equation}

=3.39+log (0.0693/0.0317)=3.39+0.34=3.73

pH=3.73

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How do i convert decimals into scientific notation
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5 0
3 years ago
A potassium hydroxide (KOH) solution has a molar concentration of 0.065 M, calculate the [H3O+], [OH-] and pH of the solution.
Tanya [424]

Answer:

1) [OH⁻] = 0.065 M

2) [H₃O⁺] = 1.54 x 10⁻¹³ M.

3)  pH = 12.81.

Explanation:

HCl is completely dissociated yo its ions in solution:

<em>KOH + H₂O  → H₃O⁺ + K⁺ + OH⁻, </em>

<em></em>

1) [OH⁻] = 0.065 M.

<em>2) [H₃O⁺]: </em>

∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.

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4 0
3 years ago
Determine the number of grams of magnesium oxide if you have 2.63 moles of magnesium oxide.
ANTONII [103]

The number of grams of Magnesium oxide= 106 g

<h3>Further explanation</h3>

Given

2.63 moles of Magnesium oxide

Required

mass of Magnesium oxide

Solution

The mole is the number of particles contained in a substance

<em> 1 mol = 6.02.10²³ </em>

Moles can also be determined from the amount of substance mass and its molar mass

Mol = mass : Molar mass

Mass of Magnesium oxide(MgO, MW=40.304 g/mol) :

= mol x MW

= 2.63 x 40.304

= 106 g

3 0
3 years ago
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