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Andrew [12]
3 years ago
5

If you push a crate with 50N of force for 10 meters in 5 seconds how much power dis u use​

Chemistry
2 answers:
morpeh [17]3 years ago
5 0

Answer:

Hi... Your answer is 10*50=500

slavikrds [6]3 years ago
4 0

Answer:

50x10 = 500 ; 500/5 = 100 watts

Explanation:

W/t /Force x Distance

the power is equal to the work done to the object divided by time.

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How many atoms are in 0.500mol of calcium?
creativ13 [48]

Answer:

3.01×10²³ atoms of calcium

Explanation:

number of moles = number of atoms/Avogadro's constant

n = N/NA

N = n×NA = 0.500 mol×6.02×10²³ mol^-1

N = 3.01×10²³ atoms of calcium

3 0
3 years ago
Which substance can be decomposed by chemical means
jolli1 [7]

Answer:

the answer is Compounds

Explanation:

Compounds are pure substances formed by the combination of elements; they can be decomposed by ordinary chemical means.

5 0
3 years ago
Which best describes a molecule?
lesantik [10]
I think it is the third statement
‘A unit is made up of two or more atoms’
3 0
4 years ago
Read 2 more answers
Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re
borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

                        A            +            B           ⇄        C

where;

numbers of moles = 0.386 mol C  (g)

Volume =  7.29 L

Molar concentration of C = \frac{0.386}{7.29}

= 0.053 M

                        A            +            B           ⇄        C

Initial               0                           0                      0.530    

Change          +x                          +x                       - x

Equilibrium      x                           x                      (0.0530 - x)

K = \frac{[C]}{[A][B]}

where

K is given as ; 78.2 atm-1.

So, we have:

78.2=\frac{[0.0530-x]}{[x][x]}

78.2= \frac{(0.0530-x)}{(x^2)}

78.2x^2= 0.0530-x

78.2x^2+x-0.0530=0  

Using quadratic formula;

\frac{-b+/-\sqrt{b^2-4ac} }{2a}

where; a = 78.2 ; b = 1 ; c= - 0.0530

= \frac{-b+\sqrt{b^2-4ac} }{2a}   or \frac{-b-\sqrt{b^2-4ac} }{2a}

= \frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}  or \frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}

= 0.0204  or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

     = 0.0530 - 0.0204

     = 0.0326

Total number of moles at equilibrium = 0.0204 +  0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

V = \frac{nRT}{P}

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K  (fixed constant temperature )

V (volume) = ???

V=\frac{(0.0734*0.0821*273.15)}{(1.00)}

V = 1.64604

V ≅ 1.65 L

3 0
3 years ago
20. What is the area of a piece of metal foil that measures 43.9 cm by 29.21 cm? Express the answer to
Aneli [31]

Answer:

The correct answer is b. 1280 cm^2

4 0
3 years ago
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