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Setler [38]
3 years ago
15

A mixture in which the particles are medium-sized between 1nm and 1000 nm in diameter is called a _______.

Chemistry
1 answer:
____ [38]3 years ago
3 0
The answer is <span>Colloid</span>
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Final volume of Argon gas:
DerKrebs [107]

Answer:

6.78 × 10⁻³ L

Explanation:

Step 1: Write the balanced equation

Mg₃N₂(s) + 3 H₂O(g) ⇒ 3 MgO(s) + 2 NH₃(g)

Step 2: Calculate the moles corresponding to 10.2 mL (0.0102 L) of H₂O(g)

At STP, 1 mole of H₂O(g) has a volume of 22.4 L.

0.0102 L × 1 mol/22.4 L = 4.55 × 10⁻⁴ mol

Step 3: Calculate the moles of NH₃(g) formed from 4.55 × 10⁻⁴ moles of H₂O(g)

The molar ratio of H₂O to NH₃ is 3:2. The moles of NH₃ produced are 2/3 × 4.55 × 10⁻⁴ mol = 3.03 × 10⁻⁴ mol.

Step 4: Calculate the volume corresponding to 3.03 × 10⁻⁴ moles of NH₃

At STP, 1 mole of NH₃(g) has a volume of 22.4 L.

3.03 × 10⁻⁴ mol × 22.4 L/mol = 6.78 × 10⁻³ L

3 0
3 years ago
Balance the following equation:<br> C7H602 + 02 -- CO2 + H20
azamat

Answer:

Explanation:

2C7H6O2 + 15O2 → 14CO2 + 6H2O.

5 0
3 years ago
What’s the name of this element and what is the reactivity?
ehidna [41]
I know it's chlorine because it have 17 dots which means it has 17 protons but I don't know the reactivity
7 0
3 years ago
If 3 moles of H2 react with two moles of o2 what is limiting reactant
Dominik [7]

H₂ is the limiting reactant.

<u>Explanation:</u>

H₂  reacts with O₂

The reaction would be

2H₂ + O₂ → 2H₂O

According to the balanced equation, 2 moles of H₂ reacts with 1 mole of O₂ to form 2 moles of H₂O.

The ratio of usage of H₂ and O₂ is 2 : 1 respectively

If 3 moles of H₂ and 2 moles of O₂ are present then:

3 moles of H₂ would require 1.5 moles of O₂                 ( 2 : 1 of H₂ and O₂ )

Out of 2 moles of O₂, 1.5 moles would be used and 0.5 mole would be in excess.

Therefore, H₂ is the limiting reactant as the number of moles of H₂ are not enough to use all the O₂.

8 0
3 years ago
HELP HELP HELP !!!!!!!!!!!!!!
zhuklara [117]

Answer:

approximately 83.33

Explanation:

The formula for the area of a right square pyramid is:

V= a^2(h/3)

a= base edge

h= height

The height is 10 inches, and the base edge is 5 inches. Plug it in to the formula:

V= 5^2 (10/3)

V= 25 (10/3)

V= 83.33 in^3

5 0
3 years ago
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