1 Evaporation
2 False…
The more volatile the higher it goes on the graph. The less volatile the lower it
Goes.
Answer : The final temperature of the aluminum and ethylene glycol is
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
= specific heat of aluminum =
= specific heat of ethylene glycol =
= mass of aluminum = 13.60 g
= mass of ethylene glycol = 23.27 g
= final temperature of aluminum and ethylene glycol = ?
= initial temperature of aluminium =
= initial temperature of ethylene glycol =
Now put all the given values in the above formula, we get:
Therefore, the final temperature of the aluminum and ethylene glycol is
Answer:
5.0
Explanation:
We have a buffer system formed by a weak base (C₅H₅N) and its conjugate acid (C₅H₆N⁺). We can calculate the pOH using the Henderson-Hasselbach's equation.
pOH = pKb + log [acid]/[base]
pOH = -log 1.8 × 10⁻⁹ + log 0.02/0.01
pOH = 9.0
Then, we will calculate the pH.
pH + pOH = 14
pH = 14 - pOH = 14 - 9.0 = 5.0
Answer:
You did very well and its correct.
Explanation:
Great Job!
B for sure, considering iron oxide is just fancy for rust.