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3 years ago

The rock had a mass of 500g and a density of 10 g/cm3. What is the volume of the rock

1 answer:

6 0

lets work back. The formula to find density is d= m/v. fill in the values you know.

10 = 500/v

well, we don't need to use a calculator. dividing by ten is going to the left once, and removing one value of ten.

this means you have a volume of 50.

Hope this helps! :D

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How many neutrons does carbon 16 have.

s2008m [1.1K]

Carbon-16 has 10 Neutrons.

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2 years ago

A cylinder of argon contains 50 L of Ar at 12.4 atm and 127°C . How many moles of argon are in the cylinder

joja [24]

Answer:

18.9 moles

Explanation:

We have the following data:

V = 50 L

P = 12.4 atm

T= 127°C + 273 = 400 K

R = 0.082 L.atm/K.mol (it is the gas constant)

We use the ideal gas equation to calculate the number of moles n of the gas:

PV = nRT

⇒ n = PV/RT = (12.4 atm x 50 L)/(0.082 L.atm/K.mol x 400 K) = 18.9 mol

6 0

2 years ago

The illustration to the left represents a mixture of hydrogen ( light blue ) and iodine ( purple ) reacting to form a product. I

Ksju [112]

Answer:

1. Hydrogen Iodide

2. 6 molecules of Hydrogen Iodide

3. Iodine is the limiting reagent

Explanation:

The image of the illustration in the question has been attached:

1. The illustration represents a mixture of hydrogen ( light blue ) and iodine ( purple )

H₂ + I₂ ---> 2HI

This forms hydrogen iodide.

2. In the given illustration, 6 product molecules of Hydrogen Iodide. This is indicated in the box on the right side of the illustration.

3. The limiting reagent is the reactant that determines how much of the products are made. It is the substance that is totally consumed when the chemical reaction is completed. In the box on the right side of the illustration, you will see that hydrogen which is indicated by blue is in excess. The limiting reagent is the one that is completely consumed which is the iodine.

8 0

2 years ago

Given the value of the equilibrium constant (Kc) for the equation (a), calculate the equilibrium constant for equation (b)

matrenka [14]

Answer: The value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

Explanation:

The given chemical equation follows:

$O_2(g)\rightarrow \frac{2}{3}O_3(g)+\frac{1}{2}O_2(g)$

The equilibrium constant for the above equation is $5.77\times 10^{-9}$

We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:

$3O_2(g)\rightarrow 2O_3(g)$

The equilibrium constant for this reaction will be the cube of the initial reaction.

If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{eq}'=(5.77\times 10^{-9})^3=1.92\times 10^{-25}$

Hence, the value of equilibrium constant for new reaction is $1.92\times 10^{-25}$

5 0

2 years ago

What is the difference between the hybridization of carbon atomsâ€™ valence orbitals in saturated and unsaturated hydrocarbons?

ANEK [815]

Answer:

Type of hybridisation

Explanation:

For example , saturated hydrocarbons have sp3 hybridisation while unsaturated hydrocarbons have either sp2 or sp hybridisation.

Example: Ethane( C2H6) has sp3 hybridisation and ethene(C2H4) has sp2 hybridisation and Ethyne(C2H2) has sp hybridization.

7 0

2 years ago