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Yakvenalex [24]
3 years ago
7

Identify the correct statement regarding the strength of chemical bonds.

Chemistry
1 answer:
allsm [11]3 years ago
5 0

Answer:

<h2>B)</h2><h2><u><em>brainlist plz</em></u></h2>

Explanation:

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Qué es la hidrólisis​
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Calculate the de broglie wavelength of a subatomic particle that is moving at 351 km/s if its mass is 9.11 à 10â31 kg. λ = hmuh
gregori [183]

The de Broglie wavelength of a subatomic particle is 2.09 nm.

 λ = h m v = h

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calculation is given in the image below

de Broglie wavelength λ = h/mv

                                          = (6.626 * 10^-34)/9.1 * 10^-31 *351 *10^3

                                          = 2.07 *10^-9

                                 Hence, = 2.op nm    

Learn more about de Broglie wavelength here:-brainly.com/question/16595523

#SPJ4

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2 years ago
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3 0
3 years ago
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Calculate the pH of: (a) 0.1M HCl; (b) 0.1M NaOH; (c) 3 X 10% M HNO3; (d) 5 X 10-10 M HCIO.; and (e) 2 x 10-8 M KOH.
Shtirlitz [24]

Answer:

(a) pH = -Log (0.1M) = 1

(b) pH = -Log (10^{-13}M) = 13

(c) pH = -Log (3x10^{-3}M) = 2.5

(d) pH = -Log (4.93x10^{-10}M) = 9.3

(e) pH = -Log (5^{-7}M) = 6.3

Explanation:

To calculate de pH of an acid solution the formula is:

pH = -Log ([H^{+}]) = 1

were [H^{+}] is the concentration of protons of the solution. Therefore it is necessary to know the concentration of the protons for every solution in order to solve the problem.

(a) and (c) are strong acids so they dissociate completely in aqueous solution. Thus, the concentration of the acid is the same as the protons.

(b) and (e) are strong bases so they dissociate completely in aqueous solution too. Thus, the concentration of the base is the same as the oxydriles. But in this case it is necessary to consider the water autoionization to calculate the protons concentration:

K_{w} =[H^{+} ][OH^{-}]=10^{-14}

clearing the [H^{+} ]

[H^{+} ]=\frac{10^{-14}}{[OH^{-}]}

(d) is a weak base so it is necessary to solve the equilibrium first, knowing Ka=3.24x10^{-8}

The reaction is HClO  →  H^{+} + CO^{-} so the equilibrium is

Ka=3.24x10^{-8}=\frac{x^{2}}{5x10^{-8}-x}

clearing the <em>x</em>

{x^{2}={1.62x10^{-17}-3.24x10^{-8}x}

x=[H^{+}]=4.93x10^{-10}

6 0
3 years ago
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