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kaheart [24]
2 years ago
11

____ enforced regulations primarily aim to reduce environmental pesticide contamination

Physics
1 answer:
Ket [755]2 years ago
8 0

Environmental Protection Agency enforced regulations primarily aim to reduce environmental pesticide contamination.

<h3>What is a Pesticide?</h3>

This refers to a chemical which is used to control pests and examples include insecticide, nematicide etc.

Environmental Protection Agency is government owned and ensures strict enforcement of regulations to reduce environmental pesticide contamination which could lead to death of beneficial organisms.

Read more about Environmental Protection Agency here brainly.com/question/23486143

#SPJ1

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A rock formed with 1,000 atoms of a radioactive parent element, but only contains 250 radioactive parent atoms today. If the hal
alisha [4.7K]

Answer:

age of rock is 2 million years

Explanation:

M_{R}=\frac{M_{O} }{2^{n} }

Where M_{R} is mass remaining

            M_{R} is original mass

         n= t/t(1/2) , which is the ratio of time to half life

M_{O} = 1000atoms

M_{R} =250 atoms

250 =\frac{1000}{2^{n} }

2^{n} = \frac{1000}{250}\\  2^{n} =4\\2^{n}  = 2^{2}\\ n=2

n =\frac{t}{t\frac{1}{2} }

t =t(1/2) *n

t(1/2) =1000000 years

t=1000000 *2

t=2,000,000 years

8 0
3 years ago
A parallel-plate capacitor in air has a plate separation of 1.76 cm and a plate area of
Monica [59]

Answer:

Explanation:

Plate separation, d = 1.76 cm = 0.0176 m

Area of plates, A = 25 cm^2 = 0.0025 m^2

V = 255 V

(a) Capacitance of capacitor

C = \frac{\epsilon _0A}{d}

C = \frac{8.854\times 10^{-12}\times 0.0025}{0.0176}

C = 1.258 x 10^-12 F

charge is same before and after immersion as the battery is disconnected

q = C V

q = 1.258 x 10^-12 x 255 = 3.2 x 10^-10 C

(b)

Capacitance before, C = 1.258 x 10^-12 C

capacitance after, C' = k x C = 80 x 1.258 x 10^-12 = 100.64 x 10^-12 C

Where, k is the dielectric constant of water = 80

Potential difference after immersion, V' = V / k = 255 / 80 = 3.1875 V

(c) initial energy,

U = \frac{q^{2}}{2C}

U = \frac{(3.2\times 10^{-10})^{2}}{2\times 1.258\times 10^{-12 }}=4.07\times 10^{-8}J

Final energy

U' = \frac{q^{2}}{2C'}

U' = \frac{(3.2\times 10^{-10})^{2}}{2\times 100.64\times 10^{-12}}=5.08\times 10^{-10}J

6 0
3 years ago
A visitor to the observation deck of a skyscraper manages to drop a penny over the edge. As the penny falls faster, the force du
pentagon [3]
If a coin is dropped at a relatively low altitude, it's acceleration remains constant. However, if the coin is dropped at a very high altitude, air resistance will have a significant effect. The initial acceleration of the coin will be the greatest. As it falls down, air resistance will counteract the weight of the coin. So, the acceleration will decrease. Although the acceleration decreases, the coin still accelerates, that is why it falls faster. When the air resistance fully counters the weight of the coin, the acceleration will become zero and the coin will fall at a constant speed (terminal velocity). So, the answer should be, The acceleration decreases until it reaches 0. The closest answer is.
a. The acceleration decreases.
8 0
3 years ago
Read 2 more answers
If an object with more mass is pushed with the same force as an object with less mass the object with more mass will accelerate?
expeople1 [14]

Answer:

smaller acceleration, so lower change in velocity

Explanation:

To answer this question we examine the equation that relates mass with force and with acceleration: F=m*a.

Since we want to know what happens to the acceleration, we solve for it in the equation: a=\frac{F}{m}

Notice that we are asked what happens when the force applied is the same, but now it is applied in an object with more mass (M).

We therefore would have to compare our initial form:

a=\frac{F}{m} with the new one: a=\frac{F}{M} wher the denominator is a larger quantity, therefore making our division/quotient smaller. Then, we conclude that the acceleration will be smaller, and therefore the change in velocity of the object will be lower.

5 0
3 years ago
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The momentum of a car 54,400 kg * m/s. If the car weighs 16,680N what is the velocity of the car
wariber [46]

G=mg=>m=G/g=16680/9.8=1702 kg

p=mv=>v=p/m=54400/1702=32 m/s

6 0
3 years ago
Read 2 more answers
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