The equation is linear, as you can write
An integrating factor would be
Multiplying both sides of the ODE by this yields
where the LHS is a derivative:
![\dfrac{\mathrm d}{\mathrm dx}\left[x^{1/3}y\right]=4x^{1/3}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5Bx%5E%7B1%2F3%7Dy%5Cright%5D%3D4x%5E%7B1%2F3%7D)
Integrating both sides, we get
Answer:
factorise out a and x :
but from general factorization:
a » x
b » 2
therefore:
First, the bigger square's area is 20*20= 400 cm^2
second, the circle's area is ¶r^2 = ¶(20/2)^2 = ¶(10)^2 = 100¶ cm^2
third, smaller square-- if we imagine it as 4 parts as 4 right triangles-- 1 part will be 1/2*(20/2)(20/2) = 1/2 (10)(10) = 50 cm^2 then the area of the smaller square is 4*50 = 200 cm^2
so the shaded parts = circle - smaller square =100¶ - 200 cm^2
the answer is 2
Answer:
x= 6- 3y/2 y= 4- 2x/3
Step-by-step explanation:
