The reaction for the combustion of methane can be expressed as follows.
CH4 + 2O2 --> CO2 + 2H2O
We solve first for the amount of carbon dioxide in moles by dividing the given volume by 22.4L which is the volume of 1 mole of gas at STP.
moles of CO2 = (5.6 L) / (22.4 L/1 mole)
moles of CO2 = 0.25 moles
Then, we can see that every mole of carbon dioxide will need 1 mole of methane
moles methane = (0.25 moles CO2) x (1 moles O2/1 mole CO2)
= 0.25 moles CH4
Then, multiply this by the molar mass of methane which is 16 g/mole. Thus, the answer is 4 grams methane.
Answer:
~69.744 moles of Ca
Explanation:
Using Avogadro's constant , we know that:
1 mole = 6.022 x 10^23 atoms
S0, the number of moles in 4.20 x 10^25 atoms of Ca:
=(4.20 x 10^25 x 1 )/(6.022 x 10^23)
~69.744 moles of Ca
Q2:How many atoms are in 0.35 moles of oxygen?
1 mole = 6.022 x 10^23 atoms
S0, the number of atoms in 0.35 moles of oxygen:
=[0.35 x (6.022 x 10^23)]
=2.1077 x 10^23 atoms of Oxygen
Hope it helps:)
The answer for the following question is explained below.
Therefore the total number of orbitals are " 9 ".
Explanation:
Orbital:
An orbital is a mathematical function that describes the wave-like behavior of an electron,electron pair,or the nucleons.
The total number of orbitals present in the 3rd energy level is 9.
Here,
A 3 s subshell has only one orbital.
A 3 p subshell has three orbitals.
A 3 d subshell has five orbitals.
Therefore the total number of orbitals is:
3 s = 1 orbital
3 p = 3 orbitals
3 d = 5 orbitals
total orbitals in 3rd energy level is = 1 + 3 + 5 =9
Therefore the total number of orbitals are " 9 ".
In a positively charged column, Asparate will travel the farthest followed by Threonine, Leucine and Lysine.
