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4 years ago

How many total orbitals are within the 3s, 3p, and energy level?

Chemistry

2 answers:

Nina [5.8K]4 years ago

7 0

The answer for the following question is explained below.

Therefore the total number of orbitals are " 9 ".

Explanation:

Orbital:

An orbital is a mathematical function that describes the wave-like behavior of an electron,electron pair,or the nucleons.

The total number of orbitals present in the 3rd energy level is 9.

Here,

A 3 s subshell has only one orbital.

A 3 p subshell has three orbitals.

A 3 d subshell has five orbitals.

Therefore the total number of orbitals is:

3 s = 1 orbital

3 p = 3 orbitals

3 d = 5 orbitals

total orbitals in 3rd energy level is = 1 + 3 + 5 =9

Therefore the total number of orbitals are " 9 ".

nadya68 [22]4 years ago

6 0

Answer:

Explanation:

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A sample of CO2 gas at 100 degrees Celsius has a volume of 250 mL at 760 mm Hg. How many moles of CO2 are present

Fed [463]

There are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.

HOW TO CALCULATE NUMBER OF MOLES:

The number of moles of a sample of gas can be calculated using the following formula:

PV = nRT

Where;

P = pressure of gas (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)

According to this question;

P = 760mmHg = 1 atm
T = 100°C = 100 + 273 = 373K
V = 250mL = 0.250L
n = ?

1 × 0.250 = n × 0.0821 × 373

0.250 = 30.62n

n = 0.250 ÷ 30.62

n = 8.16 × 10-³mol

Therefore, there are 8.16 × 10-³ moles of CO2 gas at 100°C with a volume of 250 mL at 760 mm Hg.

Learn more about number of moles at: brainly.com/question/4147359

6 0

3 years ago

This is a reaction going on in your muscle cells right this very minute:The enzyme triose phosphate isomerase catalyzes this rea

Arisa [49]

Explanation:

The given reaction is as follows.

$E + S \rightleftharpoons ES \xrightarrow[]{k_{2}} E + P$

Here, [E] = triose phosphate isomerase = 0.1 $nm = 0.1 \times 10^{-9}m$

[S] = Dihydroxy acetone phosphate = 5 $\mu m = 5 \times 10^{-6}m$

[P] = Glyceraldehyde-3-phosphate = 2 $\mu m = 2 \times 10^{-6}m$

Therefore, velocity of the reaction will be as follows.

v = $\frac{d[P]}{dt}$ = $\frac{K_{2}[E][S]}{K_{M} + [S]}$

where, $K_{M}$ = Michaelic menten constant = $\frac{K_{1} + K_{2}}{K_{1}}$

v = $\frac{900 \times 0.1 \times 10^{-9}m \times 5 \times 10^{-6}m}{10^{-5} + 5 \times 10^{-6}}$

= $30 \times 10^{-9} m$

or, = 30 nm/s

Hence, we can conclude that the actual velocity of the forward reaction under physiologic conditions if KM = 10 μM is 30 nm/s.

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3 years ago

The chemical equation below shows the reaction of methane (CH4) and oxygen gas (O2) to form carbon dioxide (CO2) and water (H2O)

Leona [35]

The answer you have marked is correct

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3 years ago

Calculate how many grams of oxygen form when each quantity of reactant completely reacts.. . 2HgO----->2Hg+O2

goblinko [34]

<span>6.96g HgO
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3 years ago

If a gas is initially at a pressure of nine ATM and a volume at 21 L at a temperature of 253K and the pressure is raise to 15 AT

Tom [10]

Answer:

15.0L

Explanation:

p/v = constan

(9*21)/253 =(15v)/ 302

v = (9*21*302)/(15*253)

v=15.0

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4 years ago