The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with 10.0 g of water is 13.024 grams
calculation
from the equation
CaO + H2O → Ca(OH)2,
1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2
find the moles of each reactant
moles=mass/molar mass
moles of CaO= 10 g/56 g/mol=0.179 moles
moles of H2O = 10 g/18 g/mol 0.556 moles
CaO is the limiting reagent therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles
mass= moles x molar mass
= 0.176 moles x 74 g/mol = 13.024 grams
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Hope I helped!
Answer:
The answer to your question is remplacement double
Explanation:
Data
Lead (II) nitrate = Pb(NO₃)₂
Potassium iodide = KI
Process
1.- Write the balanced chemical reaction
Pb(NO₃)₂ + 2KI ⇒ PbI₂ + 2KNO₃
2.- Conclusion
This is a remplacement double reaction because there are two reactants that interchange cations and the products are a combination of the reactants.
Sugar increases the viscosity of water
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