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Gre4nikov [31]
3 years ago
10

Complete the chemical formula for each ionic compound. Consult the periodic table to help you answer the question. magnesium nit

ride: Mg N calcium chloride: CaCl
Chemistry
1 answer:
Elena L [17]3 years ago
5 0

Answer:

Magnesium Nitride - Mg₃N₂

Calcium Chloride - CaCl₂

Explanation:

Magnesium (Mg) has a charge of +2, Nitrogen (N) has a charge of -3.

Swap the charges and you get Mg₃N₂.

Mg: 2(3) = 6

N: -3(2) = -6

The charges cancel out so the formula is correct.

Calcium (Ca) has a charge of +2, Chlorine has a charge of -1.

Swap the charges and you get CaCl₂.

Ca: 2(1) = 2

Cl: -1(2) = -2

The charges cancel out so the formula is correct.

Hope this helps. :)

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Zn + 2HCI --> ZnCl2 + H2
Elena-2011 [213]
Moles= mass\ relative formula mass(Ar)
moles of zinc= 7.9/30= 0.263
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i cba to work the rest out but the most reasonable answer is 0.24 mol however if you need to use working outs, use the formula i provided earlier
8 0
3 years ago
Look at the following enthalpy diagram. Select all that apply.
Drupady [299]

Answer:

Option 2 and 4 are correct

Explanation:

The reactants in the attached image have more enthalpy and hence less stability as they are more reactive. Thus, Product is more stable than the reactants.

This is an addition reaction in which two reactants add up to form the product.

Very less activation energy is required as the reactants themselves are unstable, possess high energy and hence are very reactive.

Reactants have more energy than the products.  

5 0
3 years ago
The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i
german
The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

0.115 mol I₂

1 - 0.115 = 0.885 mol CH₂Cl₂

We need moles of solute, which we have, and must convert our moles of solvent to kg:

0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂

We can now calculate the molality:

m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂

The molality of the iodine solution is 1.53.
5 0
3 years ago
Na2CO3 + CO2 + H2O → NaHCO3
Veseljchak [2.6K]

Answer:

i think the answer is d

Explanation:

8 0
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A judge in a juvenile court can dispose a juvenile runaway to a residential facility.
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The answer is true. I know this because it almost happened to me.

3 0
3 years ago
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