Answer: C=1
Explanation: If you round 1.04 to a single digit its 1
The concentration in mol/L of the chemist's potassium iodide solution : = 4.4 x 10⁻⁴ M
<h3>Further explanation</h3>
Given
88. μmol of Potassium iodide
200. mL volumetric flask
Required
The concentration
Solution
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Conversion :
88. μmol = 88 . 10⁺⁶ mol = 8.8 10⁻⁵ mol
200 ml = 0.2 L
The molarity :
= n : V
= 8.8.10⁻⁵ : 0.2
= 4.4 x 10⁻⁴ M
Answer:
The answer is 375.54 g of AgBr
Explanation:
Mass (g) = Concentration (mol/L) x volume (L) x Molecular Weight of AgBr (g/mol)
Mass = 2M x 1L x 187.77 g/mol
Mass = 375.54g
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