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Eduardwww [97]
3 years ago
10

American eels (Anguilla rostrata) are freshwater fish with long, slender bodies that we can treat as uniform cylinders 1.0 m lon

g and 10 cm in diameter. An eel compensates for its small jaw and teeth by holding onto prey with its mouth and then rapidly spinning its body around its long axis to tear off a piece of flesh. Eels have been recorded to spin at up to 14 revolutions per second when feeding in this way. Although this feeding method is costly in terms of energy, it allows the eel to feed on larger prey than it otherwise could. The eel has a certain amount of rotational kinetic energy when spinning at 14 spins per second. If it swam in a straight line instead, about how fast would the eel have to swim to have the same amount of kinetic energy as when it is spinning? (a) 0.5 m/s; (b) 0.7 m/s; (c) 3 m/s; (d) 5 m/s.
Physics
1 answer:
algol [13]3 years ago
5 0

Answer:

(c) 3 m/s;

Explanation:

Moment of inertia of the fish eels about its long body as axis

= 1/2 m R ² where m is mass of its body and R is radius of transverse cross section of body .

= 1/2 x m x (5 x 10⁻² )²

I  = 12.5 m x 10⁻⁴ kg m²

angular velocity of the eel

ω = 2 π n where n is revolution per second

=2 π n

= 2 π x 14

= 28π

Rotational kinetic energy

= 1/2 I ω²

= .5 x 12.5 m x 10⁻⁴  x(28π)²

= 4.8312m  J

To match this kinetic energy let eel requires to have linear velocity of V

1 / 2 m V² = 4.8312m

V = 3.10

or 3 m /s .

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Gold is the most ductile of all metals. For example, one gram of gold can be drawn into a wire 2.05 km long. The density of gold
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Answer:

Resistance of gold wire, R=1977 \times 10^3 ohm

Explanation:

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Temperature, T= 20^oC

We know that relation between volume and density is given as

Density= \frac{mass}{Volume}

Therefore, volume occupied by one gram gold is given as,

V=\frac{.001 kg}{19.3\times 10^3 Kg m^{-3}} = 5.181\times 10^{-8} m^3.........(1)

We Know that Volume of gold wire which is cylindrical in shape is given by following formula

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From equation 2 and 3

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V=A \times L...............(4)

on comparing equation 1 and equation 4, we got,

A \times L=5.181\times 10^{-8} m^3

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A=2.53\times 10^{-11}m^2

we know that resistance and resistivity are related by following formula,

Resistance = resistivity\times \frac{L}{A}................(5)

Put values of resistivity, A and L in equation 5, we got

R = \frac{2.44 \times 10^{-8} ohm.m \times 2050 m}{2.53\times 10^{-11} m^2}

R=1977 \times 10^3 ohm

Therefore resistance of gold wire, R=1977 \times 10^3 ohm

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3 years ago
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