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N76 [4]
2 years ago
14

⚠️⚠️A driver brakes to stop a car in 3.0 s. The car's momentum was 33,000

Physics
1 answer:
nlexa [21]2 years ago
3 0

Answer: 11000 N

Explanation:

Given that,

Time required to stop car = 3.0 s

The car's momentum = 33,000

kg m/s

magnitude of force = ?

Recall that impulse is equal to the change in momentum of the car, hence

Impulse (I) = Momentum

(Since I = force x time, then

Force x time = momentum)

F x 3.0 s = 33,000 kg m/s

F = 33,000kg m/s / 3.0s

F = 11,000 N

Thus, 11000N of force was used to stop the car.

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What occurs during stage one sleep
Mekhanik [1.2K]

Answer:

Stage one of sleep, also known as the transitional phase, occurs when one finds themselves floating in and out of consciousness. During this NREM stage, you may be partially awake while your mind begins to drift off. This period of drowsiness eventually leads to a light sleep

Explanation:

i found it on google

3 0
3 years ago
Two long, parallel wires are separated by 2.2 mm. Each wire has a 32-AA current, but the currents are in opposite directions. Pa
Alex

Answer:

B=1.1636*10^{-3}T

Explanation:

Given data

d_{wires}=2.2mm=0.022m\\ I_{current}=32A\\

To find

Magnitude of the net magnetic field B

Solution

The magnitude of the net magnetic field can be find as:

B=2*u\frac{I}{2\pi r}\\ B=2*(4\pi*10^{-7}  )\frac{32}{2\pi (0.022/2)} \\ B=1.1636*10^{-3}T

3 0
3 years ago
What is a galvanic cell??
Kobotan [32]
Its an electrochemical cell that derives electrical energy from spontaneous redox reactions taking place within the cell.
8 0
3 years ago
What happens if :<br> . The test charge is not tiny.
docker41 [41]

The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

<h3>How does test charge affect electric field?</h3>

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

<h3>What is a test charge used for?</h3>

The charge that is used to measure the electric field strength is directed to as a test charge since it is used to test the field strength. The test charge has a portion of charge denoted by the symbol q.

To learn more about test charge, refer

brainly.com/question/16737526

#SPJ9

3 0
2 years ago
A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.
Nataliya [291]

To solve the exercise it is necessary to take into account the definition of speed as a function of distance and time, and the speed of air in the sound, as well

v=\frac{d}{t}

Where,

V= Velocity

d= distance

t = time

Re-arrange the equation to find the distance we have,

d=vt

Replacing with our values

d= (343)(3.7)

d= 1269.1m

It is understood that the sound comes and goes across the entire lake therefore, the length of the lake is half the distance found, that is

L_{lake} = \frac{d}{2}

L_{lake} = \frac{1269.1}{2}

L_{lake} = 634.55m

Therefore the length of the lake is 634,55m

8 0
3 years ago
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