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N76 [4]
3 years ago
14

⚠️⚠️A driver brakes to stop a car in 3.0 s. The car's momentum was 33,000

Physics
1 answer:
nlexa [21]3 years ago
3 0

Answer: 11000 N

Explanation:

Given that,

Time required to stop car = 3.0 s

The car's momentum = 33,000

kg m/s

magnitude of force = ?

Recall that impulse is equal to the change in momentum of the car, hence

Impulse (I) = Momentum

(Since I = force x time, then

Force x time = momentum)

F x 3.0 s = 33,000 kg m/s

F = 33,000kg m/s / 3.0s

F = 11,000 N

Thus, 11000N of force was used to stop the car.

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A bulldozer does 4,500 J of work to push a mound of soil to the top of a ramp that is 15 m high. The ramp is at an angle of 35°
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<em>Answer</em>


Force = 170 N



<em>Explanation</em>

First find the distance (d) travelled by the bulldozer.


Sin 35 = 15/d

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Now;

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