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yuradex [85]
2 years ago
5

Two out-of-tune flutes play the same note. One produces a tone that has a frequency of 248 Hz, while the other produces 288 Hz.

When a tuning fork is sounded together with the 248-Hz tone, a beat frequency of 20.0 Hz is produced. When the same tuning fork is sounded together with the 288-Hz tone, a beat frequency of 20.0 Hz is produced. What is the frequency of the tuning fork
Physics
1 answer:
zaharov [31]2 years ago
3 0

Answer:

F = 268 Hz

Explanation:

The beat frequency is given as:

Beat Frequency = |Frequency 1 - Frequency 2|\\|

So, for the first flute and tuning fork:

20 Hz = |248 Hz - F|

where,

F = Frequency of tuning fork

F = 248 Hz ± 20 Hz

F = 268 Hz (OR) 228 Hz

Now, for the second flute and tuning fork:

20 Hz = |288 Hz - F|

where,

F = Frequency of tuning fork

F = 288 Hz ± 20 Hz

F = 268 Hz (OR) 308 Hz

Since, 268 Hz is common from both calculations. Therefore, it will be the frequency of the tuning fork.

<u>F = 268 Hz</u>

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Answer:

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Aleks [24]

Answer:

Height = 53.361 m

Explanation:

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From the given information we make the following summary

u_{1} = 0m/s

t_{1} = t

u_{2} = 43.12m/s

t_{2} = (t-2.2)s

The distance by the first balloon is

D = u_{1} t_{1}  + \frac{1}{2} at_{1}^2

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Inputting the values

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The distance traveled by the second balloon

D = u_{2} t_{2}  + \frac{1}{2} at_{2}^2

Inputting the values

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simplifying

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Substituting D of the first balloon into the D of the second balloon and solving

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Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

D = 4.9(3.3)^2\\ D = 53.361 m

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