All categories

3 years ago

Balance the equation. Help please!!

Chemistry

2 answers:

Tanzania [10]3 years ago

6 0

Hey there!:

Balanced equation:

5 SiO2 + 2 CaC2 = 5 Si + 2 CaO + 4 CO2

Reagents Products:

Si = 5 * 1 => 5 Si = 5* 1 => 5

O = 5 * 2 => 10 Ca = 2*1 => 2

Ca = 2 * 1 => 2 O = 2 * 1 => 2

C = 2* 2 = 4 C = 4 * 1 => 4

O = 4 * 2 => 8

Hope that helps!

Artemon [7]3 years ago

3 0

<h2>Answer:</h2>

Unbalanced equation:

SiO2 + CaC2 → Si + CaO + CO2

Balanced equation:

5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2

<h3>Explanation:</h3>

The chemical equation needs to be balanced so that it follows the law of conservation of mass.
A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

You might be interested in

What is the equilibrium equation for the dissociation of formic acid in water? hcooh (aq) + h2o (l) ⇌ h3o+ (aq) + hcoo- (aq)?

Pani-rosa [81]

Formic acid when in water would dissociate into ions just like any acids. It would dissociate into the hydrogen ion and the formate ion. The equilibrium dissociation equation would be written as:

<span>HCOOH (aq) + H2O (l) ⇌ H+ (aq) + HCOO- (aq)

Formic acid is a weak acid which means that when in aqueous solution it does not completely dissociate into its corresponding ions. Only a certain amount that would be dissociated so in the solution there will be HCOOH, HCOO- and H+ molecules. It is also known as Methanoic acid and an important substance for the synthesis of a number of substances. It is naturally occurring in ants.</span>

7 0

3 years ago

Water and ammonium nitrate (NH4NO3) react in an endothermic reaction in a beaker. What would you expect to observe during this r

maksim [4K]

Answer:

The beaker will get colder

Explanation:

3 0

2 years ago

What is the correct definition of a mixture?

jeka57 [31]

Answer:

a substance made by mixing other substances together.

Explanation:

A mixture is a substance made by mixing two or more substances together.

4 0

3 years ago

Read 2 more answers

enzyme‑catalyzed, single‑substrate reaction E + S − ⇀ ↽ − ES ⟶ E + P . The model can be more readily understood when comparing t

laila [671]

Complete Question

The complete question is shown on the first uploaded image

Answer:

[S]<<KM | [S]=KM | [S]>>KM | Not true

____________ | Half of the active | Reaction rate is | Increasing

$[E_{free}]$ is about | sites are filled of | independent of | $[E_{Total}]$ will

equal to $[E_{total}]$ . | | [S] | lower KM

_____________________________________________|____________

[ES] is much | | Almost all active

lower than | | sites are filled

$[E_{free}]$ | |

Explanation:

Generally the combined enzyme $[ES]$ is mathematically represented as

$[ES] = \frac{[E_{total}][S]}{K_M + [S]}----(1)$

for Michaelis-Menten equation

Where $[S]$ is the substrate concentration and $K_M$ is the Michaelis constant

Considering the statement $[S] < < K_M$

Looking at the equation $[S]$ is denominator so it can be ignored(it is far too small compared to $K_M$ ) hence the above equation becomes

$[ES] = \frac{[E_{total}][S]}{K_M}$

Since $[S]$ is less than $K_M$ it means that $\frac{[S]}{K_M} < < 1$

so it means that $[ES] < < [E_{total}]$

What this means is that the number of combined enzymes $[ES]$ i.e the number of occupied site is very small compared to the the total sites $[E_{total}]$ i.e the total enzymes concentration which means that the free sites [ $E_{free}]$ i.e the concentration of free enzymes is almost equal to $[E_{total}]$

Considering the second statement

$[S] = K_M$

So this means that equation one would now become

$[ES] = \frac{[E_{total}][S]}{2[S]} = \frac{[E_{total}]}{2}$

So this means that half of the active sites that is the total enzyme concentration are filled with S

Considering the Third Statement

$[S] >>K_M$

In this case the $K_M$ in the denominator of equation 1 would be neglected and the equation becomes

$[ES] = \frac{[E_{total}] [S]}{[S]} = [E_{total}]$

This means that almost all the sites are occupied with substrate

The rate of this reaction is mathematically defined as

$v =\frac{V_{max}[S]}{K_M [S]}$

Where v is the rate of the reaction(also know as the velocity of the reaction at a given time t) and $V_{max}$ is he maximum velocity of the reaction

In this case also the $K_M$ at the denominator would be neglected as a result of the statement hence the equation becomes

$v = \frac{V_{max}[S]}{[S]} = V_{max}$

So it means that the reaction does not depend on the concentration of substrate [S]

For the final statement(Not True ) it would match with condition that states that increasing $[E_{total}]$ will lower $K_M$

This is because $K_M$ does not depend on enzyme concentration it is a property of a enzyme

7 0

3 years ago

Please help ASAP! PLEASE DO NOT GIVE ME A RANDOM GIBBERISH ANSWER OR ELSE I WILL REPORT YOU AND GIVE YOU A LOW RATING!!!

UNO [17]

Answer:

if an object weighs more than an equal volume of water, it is more dense and will sink, and if it weighs less than an equal volume of water, it is less dense and will float.

Explanation:

Hope that helps

8 0

3 years ago