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Vikki [24]
4 years ago
10

Balance the equation. Help please!!

Chemistry
2 answers:
Tanzania [10]4 years ago
6 0

Hey there!:

Balanced equation:

5 SiO2 + 2 CaC2 = 5 Si + 2 CaO + 4 CO2

Reagents                                         Products:

Si = 5 * 1 => 5                                  Si = 5* 1 => 5

O = 5 * 2 => 10                                Ca = 2*1 => 2

Ca = 2 * 1 => 2                                 O = 2 * 1 => 2

C = 2* 2 = 4                                      C = 4 * 1 => 4

                                                         O = 4 * 2 => 8


Hope that helps!

Artemon [7]4 years ago
3 0
<h2>Answer:</h2>

Unbalanced equation:

                                      SiO2 + CaC2 → Si + CaO + CO2

Balanced equation:

                                    5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2

<h3>Explanation:</h3>
  • The chemical equation needs to be balanced so that it follows the law of conservation of mass.
  • A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

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8 0
3 years ago
uppose the reaction Ca3(PO4)2 + 3H2SO4 ï‚® 3CaSO4 + 2H3PO4 is carried out starting with 153 g of Ca3(PO4)2 and 87.6 g of H2SO4.
aleksklad [387]

The answer is 58.4 g of H₃PO₄

Given that mass of Ca₃(PO₄)₂ is 153g

mass of H₂SO₄ is 87.6g

We need to calculate the mass of H₃PO₄

So the balanced chemical reaction is

Ca₃(PO₄)₂  +  3H₂SO₄  ⇒   3CaSO₄  +  2H₃PO₄

Let us calculate the molar mass of the reactants

Ca₃(PO₄)₂ = (3 x 40) + (2 x 31) + (8 x 16)

= 120 + 62 + 128

= 310 g

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4)

= 2 + 32 + 64

= 98 g

Now let us calculate the limiting reactant

The Theoretical Yield =  Ca₃(PO₄)₂ / H₂SO₄

= 310 / 3(98)

= 1.05

The Experimental yield

Ca₃(PO₄)₂ / H₂SO₄

= 153 / 87.6 = 1.74

Because the observed percentage was more than the predicted proportion, H2SO4 is the limiting reactant.

Let us Calculate the molar mass of H₃PO₄

H₃PO₄ = (1 x 3) + (31 x 1) + (16 x 4)

= 3 + 31 + 64

= 98 g

Now Calculate the mass of H₃PO₄

3(98) g of H₂SO₄ ------------------ 2(98) g of H₃PO₄

87.6 g of H₂SO₄ ------------------  x

x = ( 87.6 x 2 x 98) / (3 x 98)

x = 17169.6 / 294

x = 58.4g of H₃PO₄

Learn more about Theoretical Yield here

brainly.com/question/25996347

#SPJ1

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2 years ago
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4 0
4 years ago
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Answer:

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