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madreJ [45]
3 years ago
7

Find the number of moles of CO2− 3 produced when 0.207 mol of sodium carbonate dissolved. Answer in units of mol.

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
6 0

Answer : The number of moles of carbonate ion, (CO_3^{2-}) produced are, 0.207 moles.

Explanation : Given,

Moles of sodium carbonate = 0.207 mol

As we know that when sodium carbonate dissolved in water then it dissociates to give 2 sodium ion and 1 carbonate ion.

The balanced chemical reaction will be:

Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^{2-}(aq)

From the balanced chemical reaction we conclude that,

As, 1 mole of sodium carbonate dissociate to give 1 moles of carbonate ion, (CO_3^{2-})

So, 0.207 mole of sodium carbonate dissociate to give 0.207 moles of carbonate ion, (CO_3^{2-})

Thus, the number of moles of carbonate ion, (CO_3^{2-}) produced are, 0.207 moles.

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Answer:

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Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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0.00684 moles potassium sulfate react with 0.00684 mole of lead(II) acetate

Moles of lead(II) acetate = 0.004189 moles

Limiting reagent is the one which is present in small amount. Thus, lead(II) acetate is limiting reagent. ( 0.004189 < 0.00684)

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1 mole of lead(II) acetate gives 1 mole of lead(II) sulfate

0.004189 mole of lead(II) acetate gives 0.004189 mole of lead(II) sulfate

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