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2 years ago

Which compound has the highest boiling point? HF, HI, HBr, HCl, or F2?

Chemistry

1 answer:

Kisachek [45]2 years ago

3 0

Answer:

Explanation:

This concept can be understood from the knowledge of Intermolecular forces of attraction.

Intermolecular bonds are Van der Waals forces which are weak forces of attraction joining non-polar and polar molecules together. They exist in the form of London Dispersion Forces and Dipole-dipole attraction.

An example of Dipole-dipole attraction is the hydrogen bond which is a unique dipole-dipole attraction between polar molecules in which a hydrogen atom is directly joined to a highly electronegative atom such as fluorine, oxygen, or nitrogen).

Molecules that possess the characteristics of hydrogen bonding have a higher boiling point. In the given question, only HF undergo hydrogen bond due to the electronegative effect of the fluorine element.

F2 occurs as a weak London dispersion force and it occurs between non-polar molecules.

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Convert 31.9 g of N2 to moles

pashok25 [27]

Answer: 1.14mol

Nitrogen molar mass=14g/mol

N2 molar mass=14*2=28g/mol

31.9g(1/28)=1.14mol N2

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3 years ago

Write a scientific report on the clouds seeding using condensation nuclei and showing its relationship to saturated solutions.

Andrej [43]

Answer:

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Explanation:

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2 years ago

Draw a mechanism for this reaction. 5-hydroxypentanoic acid forms 2-oxanone in the presence of acid. draw all missing reactants

Licemer1 [7]

Answer: -

The first step involves protonation of the carbonyl oxygen.

After protonation, the Alcohol oxygen now attacks the carbon of the carbonyl.

Thus a six membered ring is formed with 5 carbon atoms and 1 oxygen atom. The 1st position carbon atom has 2 OH groups.

One of these gets again protonated.

This leaves as water. With the loss of the H+, there results a carbonyl at 1 position.

Thus 5-hydroxypentanoic acid forms a lactone or 2-oxanone in presence of acid.

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3 years ago

The product of the nitration reaction will have a nitro group at which position with respect to the methyl group? Group of answe

zimovet [89]

Answer:

Mostly Para

Explanation:

First, let's assume that the molecule is the toluene (A benzene with a methyl group as radical).

Now the nitration reaction is a reaction in which the nitric acid in presence of sulfuric acid, react with the benzene molecule, to introduce the nitro group into the molecule. The nitro group is a relative strong deactiviting group and is metha director, so, further reactions that occur will be in the metha position.

Now, in this case, the methyl group is a weak activating group in the molecule of benzene, and is always ortho and para director for the simple fact that this molecule (The methyl group) is a donor of electrons instead of atracting group of electrons. Therefore for these two reasons, when the nitration occurs,it will go to the ortho or para position.

Now which position will prefer to go? it's true it can go either ortho or para, however, let's use the steric hindrance principle. Although the methyl group it's not a very voluminous and big molecule, it still exerts a little steric hindrance, and the nitro group would rather go to a position where no molecule is present so it can attach easily. It's like you have two doors that lead to the same place, but in one door you have a kid in the middle and the other door is free to go, you'll rather pass by the door which is free instead of the door with the kid in the middle even though you can pass for that door too. Same thing happens here. Therefore the correct option will be mostly para.

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3 years ago

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jasenka [17]

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2 years ago

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