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nadya68 [22]
3 years ago
8

The client's lab values are sodium 166 mEq/L, potassium 5.0 mEq/L, chloride 115 mEq/L, and bicarbonate 35 mEq/L. What condition

is this client likely to have, judging by anion gap?
Chemistry
1 answer:
Fantom [35]3 years ago
5 0

Answer:

The anion value of 21mEq/L suggest the client will have metabolic acidosis

Explanation:

Anion gap is the interval or difference between measured cations (Sodium and Potassium) with the sum of measured anions (chloride and bicarbonate)

Using the above mentioned data

(166 + 5) - (115 + 35)  =  21mEq/L

Therefore the Anion gap = 21mEq/L

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My cat, Copper, is a picky eater. I've noticed that he eats better when the TV is on. To
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I was going to help but I don’t understand the question
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3 years ago
What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te
Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

5 0
2 years ago
What volume of 0.4567 m h2so4 is required to neutralize 30.00 ml of 0.3210 m naoh?
sertanlavr [38]
Answer is: volume of H₂SO₄ is 42.1 mL.<span>
Chemical reaction: H</span>₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.<span>
c(H</span>₂SO₄) = 0,4567 M = 0,4567 mol/L.<span>
V(NaOH) = 30 mL </span>÷ 1000 mL/L <span>= 0,03 L.
c(NaOH) = 0,321 M = 0,321 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,321 mol/L · 0,030 L.
n(NaOH) = 0,00963 mol.
From chemical reaction: n(H</span>₂SO₄) : n(NaOH) = 1 : 2.<span>
n(H</span>₂SO₄) = 0,01926 mol.<span>
V(H</span>₂SO₄) = n(H₂SO₄) ÷ c(H₂SO₄).<span>
V(H</span>₂SO₄) = 0,01926 mol ÷ 0,4567 mol/L.<span>
V(H</span>₂SO₄<span>) = 0,0421 L = 42,1 mL.</span>
3 0
2 years ago
Consider a 400 mL solution of 0.10 M \ce{NaOH}NaOH. Calculate the mass of solid \ce{NaOH}NaOH required to achieve this solution.
AnnyKZ [126]

Answer:

Is 40.10 ml

Explanation:

i've dome it before

3 0
1 year ago
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