1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Komok [63]
3 years ago
13

Is the electron configuration given below for an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition

metal.
(a) 1s2 2s2 2p6 3s2 3p5
(b) 1s2 2s2 2p6 3s2 3p6 3d7 4s2
(c) 1s2 2s2 2p6 3s2 3p6 3d7 4s2 4p6
(d) 1s2 2s2 2p6 3s2 3p6 3d7 4s1
Chemistry
1 answer:
OleMash [197]3 years ago
7 0

Answer :

(a) 1s^22s^22p^63s^23p^5   → Halogen

(b) 1s^22s^22p^63s^23p^63d^74s^2    → Transition metal

(c) 1s^22s^22p^63s^23p^63d^{10}4s^24p^6   → Transition metal

(d) 1s^22s^22p^63s^23p^63d^4s^1   → Transition metal

Explanation :

Inert gas : These are the gases which lie in group 18.

Their general electronic configuration is: ns^2np^6 where n is the outermost shell.

Halogen : These are the elements which lie in group 17.

Their general electronic configuration is: ns^2np^5 where n is the outermost shell.

An alkali metal : These are the elements which lie in group 1.

Their general electronic configuration is: ns^1 where n is the outermost shell.

An alkaline earth metal : These are the elements which lie in group 2.

Their general electronic configuration is: ns^2 where n is the outermost shell.

Transition elements : They are the elements which lie between 's' and 'p' block elements. These are the elements which lie in group 3 to 12. The valence electrons of these elements enter d-orbital.

Their general electronic configuration is: (n-1)d^{1-10}ns^{0-2} where n is the outermost shell.

(a) 1s^22s^22p^63s^23p^5

The element having this electronic configuration belongs to the halogen family.

(b) 1s^22s^22p^63s^23p^63d^74s^2

The element having this electronic configuration belongs to the transition family.

(c) 1s^22s^22p^63s^23p^63d^{10}4s^24p^6

The element having this electronic configuration belongs to the transition family.

(d) 1s^22s^22p^63s^23p^63d^4s^1

The element having this electronic configuration belongs to the transition family.

You might be interested in
Consider a sample of 3.5 mol of N2(g) at T1 = 350 K, that undergoes a reversible and adiabatic change in pressure from p1 = 1.50
devlian [24]

Answer:

Part A is just T2 = 58.3 K

Part B ∆U = 10967.6 x C_{V} You can work out C_{V}

Part C

Part D

Part E

Part F

Explanation:

P = n (RT/V)

V = (nR/P) T

P1V1 = P2V2

P1/T1 = P2/T2

V1/T1 = V2/T2

P = Pressure(atm)

n = Moles

T = Temperature(K)

V = Volume(L)

R = 8.314 Joule or 0.08206 L·atm·mol−1·K−1.

bar = 0.986923 atm

N = 14g/mol

N2 Molar Mass 28g

n = 3.5 mol N2

T1 = 350K

P1 = 1.5 bar = 1.4803845 atm

P2 = 0.25 bar = 0.24673075 atm

Heat Capacity at Constant Volume

Q = nCVΔT

Polyatomic gas: CV = 3R

P = n (RT/V)

0.986923 atm x 1.5 = 3.5 mol x ((0.08206 L atm mol -1 K-1 x 350 K) / V))

V = (nR/P) T

V = ((3.5 mol x 0.08206 L atm mol -1 K-1)/(1.5 x 0.986923 atm) )x 350K

V = (0.28721/1.4803845) x 350

V = 0.194 x 350

V = 67.9036 L

So V1 = 67.9036 L

P1V1 = P2V2

1.4803845 atm x 67.9036 L = 0.24673075 x V2

100.52343693 = 0.24673075 x V2

V2 = P1V1/P2

V2 = 100.52343693/0.24673075

V2 = 407.4216 L

P1/T1 = P2/T2

1.4803845 atm / 350 K = 0.24673075 atm / T2

0.00422967 = 0.24673075 /T2

T2 = 0.24673075/0.00422967

T2 = 58.3 K

∆U= nC_{V} ∆T

Polyatomic gas: C_{V} = 3R

∆U= nC_{V} ∆T

∆U= 28g x C_{V} x (350K - 58.3K)

∆U = 28C_{V} x 291.7

∆U = 10967.6 x C_{V}

5 0
3 years ago
Conditions to light Bend
lisabon 2012 [21]
When it passes from one medium
8 0
3 years ago
2 days Claire went missing, the body of a young girl was found in an abandoned building. There were 2 blowfly larvae on the body
KengaRu [80]

Answer:

Yes it is possible that the body might be Claire's

Explanation:

It is possible because the scenario says that it had similar appearances that Claire had

8 0
3 years ago
What is the physical process whereby atoms or molecules tend to move from an area of higher concentration or pressure to an area
34kurt

Diffusion is the physical process whereby atoms or molecules tend to move from an area of higher concentration or pressure to an area of lower concentration or pressure.

In the field of science, diffusion can be described as a process in which molecules move along the concentration gradient i,e from a region of higher concentration to a region of lower concentration.

The process of diffusion is extremely useful in many everyday living conditions. For example, it is due to diffusion that carbon dioxide and oxygen are exchanged between the lungs and the blood. Diffusion of water, salts, and water is an important process that occurs in the kidneys.

We can divide diffusion into two main types which are simple diffusion and facilitated diffusion. Simple diffusion occurs without any carrier molecule. On the other hand, facilitated diffusion occurs with aid of a carrier molecule.

To learn more about diffusion, click here:

brainly.com/question/94094

#SPJ4

4 0
1 year ago
How many moles are contained 80.3 gram of sm(no3)3
swat32
<h3>Answer:</h3>

0.239 mol Sm(NO₃)₃

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 80.3 g Sm(NO₃)₃

[Solve] moles Sm(NO₃)₃

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Sm - 150.36 g/mol

[PT] Molar Mass of N - 14.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of Sm(NO₃)₃ - 150.36 + 3[14.01 + 3(16.00)] = 336.39 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                 \displaystyle 80.3 \ g \ Sm(NO_3)_3(\frac{1  \ mol \ Sm(NO_3)_3}{336.39 \ g \ Sm(NO_3)_3})
  2. [DA] Divide [Cancel out units]:                                                                        \displaystyle 0.238711 \ mol \ Sm(NO_3)_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.238711 mol Sm(NO₃)₃ ≈ 0.239 mol Sm(NO₃)₃

3 0
2 years ago
Other questions:
  • Which of the following is a solution? <br> Steel <br> Milk <br> Plastic <br> Water
    9·1 answer
  • A compound composed of nickel and fluorine contains 9.11 g ni and 5.89 g f. what is the empirical formula of this compound
    8·1 answer
  • Photosynthesis is very important to us. Name 3 different types of ways you benefit from photosynthesis each day
    6·1 answer
  • Iron forms rust, expressed as Fe2O3.
    6·1 answer
  • Usually hard but brittle<br> Ionic or covalent
    7·2 answers
  • Why is it important for scientists to keep testing a hypothesis even after they’ve found it to be true?
    11·1 answer
  • 60.0 g of NH Cl are dissolved in 100 grams of water at 60.0° C. This solution is
    6·1 answer
  • Explanation and answer and you’ll get brain list
    15·1 answer
  • Helpppppppppppppppppppppppppppppppppp
    11·2 answers
  • What do anions like F do to fulfill the octet rule?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!