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GrogVix [38]
3 years ago
10

The atomic mass of an element is found by which of the following methods?

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
8 0
On the periodic table it is the number on the bottom of the element. 
<span>If you know the amount of neutrons you can add it to the number of protons to find the atomic mass NUMBER, which is a good approximate of the atomic mass. </span>
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If 4520 kj of heat is needed to boil a sample of water, what is the mass of water
Cerrena [4.2K]

Answer:

1,085g of water

Explanation:

If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

                                                  Q= m*C*Δt  where;

Q in the heat, in this case: 4520kj

m is the mas

Δt= is the difference between final-initial temperature (change of temperature), in this exercise we don´t have temperatura change.

In order to determine the mass, I will have the same equation but finding m

                                          m= Q/C*Δt    without   m=Q/C

So: m= 4,520J/4.18J/g°C

      m= 1,0813 g

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3 years ago
What percentage of radioactive substance remains after two half-lives
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Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

3 0
3 years ago
27 Which energy conversion must occur in an operating electrolytic cell?
Vitek1552 [10]
<u> electrical energy to chemical energy</u>
5 0
3 years ago
For each pair of gases, select one that most likely has the highest rate of effusion. Use the periodic table if necessary
brilliants [131]
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4 0
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Read 2 more answers
If a gas is initially at a pressure of 9 atm, a volume of 21 liters, and a temperature of 253 K, and then the pressure is raised
alex41 [277]

Answer:

15.04 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

Given ,  

V₁ = 21 L

V₂ = ?

P₁ = 9 atm

P₂ = 15 atm

T₁ = 253 K

T₂ = 302 K

Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

\frac {{9}\times {21}}{253}=\frac {{15}\times {V_2}}{302}

Solving for V₂ , we get:

<u>V₂ = 15.04 mL</u>

3 0
3 years ago
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