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3 years ago

What kind of matter is smoke

Chemistry

2 answers:

Anton [14]3 years ago

8 0

The answer is C.

Smoke is defined as a colloid, which is any substance consisting of particles substantially larger than atoms or ordinary molecules. It is a suspension of solid and or liquid particles in the air.

Naily [24]3 years ago

7 0

The answer is C. Suspension olloid.

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1. Define flash flood.

BigorU [14]

A flash flood is when to much water overflows a certain area. This is common with storms. When it rains; small bridges tend to floor. Garages, basements, and cellars can tend to flood as well from storms.

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3 years ago

Read 2 more answers

Bases in solution produce what type of ions?

Natali [406]

Bases produce hydroxide ions, while acids produce hydrogen ions.

Bases have a pH of above 7, and are bitter and slippery.

Answer: <span>c. hydroxide ions</span>

4 0

3 years ago

All the following are signs of a chemical reaction, except

hodyreva [135]

C. a change of state. It can be a physical or a chemical state of change.

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3 years ago

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A solution contains one or more of the following ions: Ag , Ca2 , and Co2 . Lithium bromide is added to the solution and no prec

koban [17]

Answer:

$Ca^{2+} and Co^{2+}$

Explanation:

Given:

A solution contains one or more of the following ions such as Ag, $Ca_2$ and $Co_2$

Here the Lithium bromide is added to the solution and no precipitate forms

Solution:

Since with LiBr no precipitation takes place therefore Ag+ is absent

Here on adding $Li_2SO_4$ to it precipitation takes place.

Precipitate is as follows,

$Ca^{2+}(aq)+SO_4^2^-(aq)----->CASO_4(s)$

Thus,

$Ca^2^+$ is present

When $Li_3PO_4$ is added again precipitation takes place.

Therefore the reaction is as follows,

$Co^2^+(aq)+PO_4^3^-(aq)------>Co_3(PO_4)_2(s)$

Therefore,

$Ca^{2+} and Co^{2+}$ are present in the solution

3 0

3 years ago

The element in Group 14 Period 4 has how many neutrons and is it a metal, nonmetal, metalloid or noble gas.

monitta

Number of neutrons=41, and it is metalloid

<h3>Further explanation</h3>

Group 14⇒valence electron = 4(ns²np²)

Period 4⇒n=4

So electron configuration of the element :

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p² = 32 electron=atomic number

The element with atomic number 32, which is in period 4 and group 14 is Ge-Germanium

There are seven elements that can be classified as metalloids, namely boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), and polonium (Po).

While the mass number: 73

So the number of neutrons = mass number-atomic number

$\tt 73-32=41$

8 0

2 years ago