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MAVERICK [17]
2 years ago
12

If a star is 720 , 000 , 000 , 000 , 000 meters from Earth, how many seconds does it take light to travel from the Earth to the

star
Physics
1 answer:
Minchanka [31]2 years ago
5 0

Answer:

anywhere between 100000 to about 400000 human years .

Explanation:

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Define fundamental unit ? write its two example. ​
stealth61 [152]

the International System of Units, the fundamental units are: The meter (symbol: m), used to measure length. The kilogram (symbol: kg), used to measure mass. The second (symbol: s), used to measure time. The ampere (symbol: A), used to measure electric current.

8 0
3 years ago
A medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. This increased p
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Hyperbaric Oxygen Therapy (HBOT) is a medical treatment where the individual breathes in pure oxygen while in a pressurized room or through a tube. The HBOT treatment includes breathing 100% oxygen while under increased atmospheric pressure. It is used <span>for decompression sickness by scuba divers.</span>
5 0
3 years ago
Where is the epicenter of the hypothetical earthquake as shown in the illustration below?
Genrish500 [490]

Answer:

Point D

Explanation:

The epicenter of a hypothetical earthquake is located at the point where the earthquake begins.

(See the attached image).

Hope it helps!

5 0
3 years ago
Describe all the characteristics of Earth that make it ideal for living creatures.
Lady_Fox [76]
Earths atmosphere, Temperature, Plant life and Oxygen I guess
8 0
3 years ago
Read 2 more answers
ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs
inessss [21]

Answer:

Part a)

m_2 = 4.9 \times 10^7 kg

Part b)

q_1 = q_2 = 5312.6 C

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

F = m_1a_1 = m_2a_2

here we have

6.3 \times 10^7(7) = m_2(9)

now we have

m_2 = 4.9 \times 10^7 kg

Part b)

Now for the force between two charges we can say

F = \frac{kq_1q_2}{r^2}

now we have

(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}

now we have

q_1 = q_2 = 5312.6 C

3 0
3 years ago
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