Force on left crate, right crate and truck we need to draw here
First we will write the equation for left crate
Now similarly for right crate
now for truck
Now we know that F = 200 N
now add all three equation
now we will find all tension using this value of acceleration
Yes, these two objects have different masses.
<h3>How can we calculate that this statement is right ?</h3>To calculate the precision of mass we are using the formula,
Precision(P) =
Or,m=
-m₁
For the first case we are given,
m₁= The recorded value of mass
= 128.01 g
P= Precision of the mass
=0.005g
So, according to the formula, m will be,
m=
-128.01
Or,m=25,473.99 g
Or,m=25.47 Kg
For the first case m is 25.47 Kg..
For the second case we are given,
m₁= The recorded value of mass
= 0.13 Kg
P= Precision of the mass
=0.005 Kg
So, according to the formula, m will be,
m=
-0.13
Or,m= 25.87 kg
For the second case m is 25.87 Kg.
For the two cases m has different values, 25.47 Kg≠25.87 Kg.
Therefore we can conclude that, these two objects have different masses.
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