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Fudgin [204]
3 years ago
7

A 1100 kg car pushes a 1800 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the

car push against the ground with a force of 4500 N.A) What is the magnitude of the force of the car on the truck?B) What is the magnitude of the force of the truck on the car?
Physics
1 answer:
12345 [234]3 years ago
6 0

Answer:The answer is 3000 N.

Force (F) is the multiplication of mass (m) and acceleration (a).

F = m · a

It is given:

mc = 1000 kg

mt = 2000 kg

total force: F = 4500 N 

total mass: m = mc + mt

Let's calculate acceleration which is common:

a = F/m = F/(mc + mt) = 4500/(1000 + 2000) = 4500/3000 = 1.5 m/s²

Now, when we know acceleration, let's calculate force on the truck:

Ft = mt · a = 2000 · 1.5 = 3000 N

Explanation:

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Basile [38]

Answer: The first one

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If a 100 N net force acts on a 50 kg car, what will the acceleration of the car will be?
Allushta [10]
According to newton's law Force = mass * acceleration
so , 100 = 50 * a
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6 0
3 years ago
a person runs 27.0km west then turns around and runs 13.0km east what's the distance and displacement ?
Alexxandr [17]

Answer:

See below

Explanation:

Distance = 27 + 13 = 40 km

Displacement = 27 - 13 = 14 km

7 0
3 years ago
A torsion-bar spring consists of a prismatic bar, usually of round cross section, that is twisted at one end and held fast at th
ra1l [238]

Answer:

d₁ = 0.29 in

d₂ = 0.505 in

Explanation:

Given:

T = 1500 lbf in

L = 10 in

x = 0.5 L = 5 in

T_{1} =\frac{T(L-x)}{L} =\frac{1500*(10-5)}{10} =750lbfin

First case: T = T₁ + T₂

T₂ = T - T₁ = 1500 - 750 = 750 lbf in

If the shafts are in series:

θ = θ₁ + θ₂

θ = ((T₁ * L₁)/GJ) + ((T₂ * L₂)/GJ)

Second case: If d₁ ≠ d₂

θ = ((T₁ * L₁)/GJ₁) + ((T₂ * L₂)/GJ₂) = 0 (eq. 1)

t₁ = t₂

\frac{16T_{1} }{\pi d_{1}^{3}  } =\frac{16T_{2} }{\pi d_{2}^{3}  } (eq. 2)

T₁ + T₂ = 1500 (eq. 3)

θ₁ first case = θ₁ second case

Replacing:

\frac{750*5}{G(\frac{\pi }{32})*0.5^{4}  } =\frac{T_{1}*3.7 }{G(\frac{\pi }{32})*d_{1} ^{4}  }\\T_{1} =16216d_{1} ^{4}

The same way to θ₂:

\frac{750*5}{G(\frac{\pi }{32})*0.5^{4}  } =\frac{T_{2}*6.3 }{G(\frac{\pi }{32})*d_{2} ^{4}  } \\T_{2} =9523.8d_{2} ^{4}

From equation 2, we have:

d₁ = 0.587 * d₂

From equation 3, we have:

d₂ = 0.505 in

d₁ = 0.29 in

7 0
3 years ago
What do radio waves and gamma rays have in common?
Nastasia [14]

Answer:

A - They are both electromagnetic waves.

Explanation:

Electromagnetic waves are waves consisting of periodic oscillations of electric and magnetic fields, that vibrate in a plane perpendicular to the direction of propagation of the wave (for this reason, they are said to be "transverse waves").

Electromagnetic waves, unlike mechanical waves, can travel through a vacuum, and do not need a medium to propagate. Their speed in a vacuum is a constant and it is called speed of light (c=3.0\cdot 10^8 m/s).

Electromagnetic waves are classified, depending on their wavelength and frequency, into 7 different types - together they form the electromagnetic spectrum. The 7 types, listed from shortest to longest wavelength, are:

gamma rays

X-rays

ultraviolet radiation

visible light

infrared radiation

microwaves

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All these waves, despite having different properties, are all electromagnetic waves -so we see that both radio waves and gamma rays belong to this type of waves.

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3 years ago
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