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Bad White [126]
3 years ago
12

A backpack has a mass of 8 kg. it is lifted and given 54.9 J of gravitational potential energy. how high is it lifted? Accelerat

ion due to gravity is g = 9.8 m/s^2. A) 3.2 m B) 0.15 m C) 6.9 m D) 0.7 m
Physics
1 answer:
masya89 [10]3 years ago
4 0

Answer:

<h2>0.7 m</h2>

Option D is the correct option.

solution,

Potential Energy(PE)=54.9 J

Mass(m)=8 kg

Acceleration due to gravity (g)=9.8 m/s^2

Height (h)=?

Now,

p.e = m \times g \times h \\ or \: 54.9 = 8 \times 9.8 \times h \\ or \: 54.9 = 78.4 \times h \\ or \: h =  \frac{54 .9}{78.4}  \\ h = 0.7 \: m

Hope this helps...

Good luck on your assignment..

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2 years ago
A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista
slamgirl [31]

Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

C' = \frac{1}{2}C

The potential difference across the capacitor is given by

V= \frac{Q}{C}

where

Q is the charge on the plates

C is the capacitance

We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

V' = 2 V

Now we can analyze the electric field between the plates of the capacitor, which is given by

E=\frac{V}{d}

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

E'=\frac{2V}{2d}=\frac{V}{d}=E

So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:

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Then the force on the particle will stay the same.

4 0
3 years ago
A stone is launched straight up by a slingshot. Its initial speed is 19.6 m/s, and the stone is 1.50 m above the ground when lau
arlik [135]

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Explanation:

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g is acceleration due to gravity = 10m/s²

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H = 19.21m

b) The time elapsed before the stone hits the ground is the time of flight T= 2U/g

T= 2(19.6)/10

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5 0
3 years ago
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ivann1987 [24]

Answer:

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To answer this question, let's write Newton's second law of the two axes

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   The direction of this force is along the length of the rods that are in an Angle, where the x and y components of the force come from

In general this force is small because the rubbing of the skis is small

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kramer

Answer:

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3 0
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