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Bad White [126]
3 years ago
12

A backpack has a mass of 8 kg. it is lifted and given 54.9 J of gravitational potential energy. how high is it lifted? Accelerat

ion due to gravity is g = 9.8 m/s^2. A) 3.2 m B) 0.15 m C) 6.9 m D) 0.7 m
Physics
1 answer:
masya89 [10]3 years ago
4 0

Answer:

<h2>0.7 m</h2>

Option D is the correct option.

solution,

Potential Energy(PE)=54.9 J

Mass(m)=8 kg

Acceleration due to gravity (g)=9.8 m/s^2

Height (h)=?

Now,

p.e = m \times g \times h \\ or \: 54.9 = 8 \times 9.8 \times h \\ or \: 54.9 = 78.4 \times h \\ or \: h =  \frac{54 .9}{78.4}  \\ h = 0.7 \: m

Hope this helps...

Good luck on your assignment..

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Answer:

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Read 2 more answers
A ball is thrown directly downward with an initial speed of 7.70 m/s, from a height of 30.2 m. After what time interval does it
KatRina [158]

Answer:

t = 1.82

Explanation:

Given

u = 7.70m/s -- initial velocity

s = 30.2m --- height

Required

Determine the time to hit the ground

This will be solved using the following motion equation.

s = ut + \frac{1}{2}gt^2

Where

g = 9,8m/s^2

So, we have:

30.2 = 7.70t + \frac{1}{2} * 9.8 * t^2

30.2 = 7.70t + 4.9 * t^2

Subtract 30.2 from both sides

30.2 -30.2  = 7.70t + 4.9 * t^2 - 30.2

0  = 7.70t + 4.9 * t^2 - 30.2

0  = 7.70t + 4.9t^2 - 30.2

7.70t + 4.9t^2 - 30.2  = 0

4.9t^2 + 7.70t - 30.2  = 0

Solve using quadratic formula:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = 4.9;\ b = 7.70;\ c = -30.2

t = \frac{-7.70\±\sqrt{7.70^2 - 4*4.9*-30.2}}{2*4.9}

t = \frac{-7.70\±\sqrt{651.21}}{9.8}

t = \frac{-7.70\±25.52}{9.8}

Split the expression

t = \frac{-7.70+25.52}{9.8} or t = \frac{-7.70-25.52}{9.8}

t = \frac{17.82}{9.8} or t = -\frac{33.22}{9.8}

Time can't be negative;  So, we have:

t = \frac{17.82}{9.8}

t = 1.82

Hence, the time to hit the ground is 1.82 seconds

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DerKrebs [107]

Answer:

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Explanation:

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