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Nastasia [14]
3 years ago
10

Aqueous hydrogen chloride reacts with oxygen gas to form chlorine gas and liquid water.Express your answer as a balanced chemica

l equation. Identify all of the phases in your answer
Chemistry
2 answers:
zhenek [66]3 years ago
8 0

4HCl (aq) + O₂ (g) ⇒ 2Cl₂ (g) + 2H₂O (l)

<h3>Further explanation </h3>

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product
  • 3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C, H and the last O

Reaction :

HCl (aq) + O₂ (g) ⇒ Cl₂ (g) + H₂O (l)

Suppose we give a coefficient of 1 for HCl

HCl (aq) + aO₂ (g) ⇒ bCl₂ (g) + cH₂O (l)

number of Homs: left 1, right 2c -> 2c = 1-> c = 1/2

number of Cloms: left 1, right 2b ---> 2b = 1 ----> b = 1/2

number of O atoms: left 2a, right c ---> 2a = c ---> 2a = 1/2 ---> a = 1/4

the reaction coefficient becomes:

\rm HCl(aq)+\dfrac{1}{4}O_2(g)\Rightarrow \dfrac{1}{2}Cl_2(g)+\dfrac{1}{2}H_2O(l)\times 4\\\\4HCl(aq)+O_2(g)\Rightarrow 2Cl_2(g)+2H_2O(l)

<h3>Learn more </h3>

the combustion of octane in gasoline

brainly.com/question/8175791

brainly.com/question/897044

hydrogen and excess oxygen

brainly.com/question/1405182

ddd [48]3 years ago
5 0

Answer: 4 HCl (g) + O₂ (g) → 2 Cl₂ (g) + 2 H₂O (l)

Explanation:

4 moles of hydrogen chloride (note that it is in the gaseous phase, otherwise it would be hydrochloric acid) react with 1 mole of oxygen gas to form 2 moles of chlorine gas and 2 moles of liquid water.

To conform with  the law of conservation of mass, the equation must be balanced, this means that there must be the same number of each type of atom  on both sides of the arrow.

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