Since we started with 50 mL of the titrant and 32 mL of a 2.5 M standard solution. Using the dilution equation M2 = 2.5 M × 32 mL/50 mL
Titration is a means of determining the concentration of a solution by using another solution of known concentration. The solution of known concentration is called the standard solution.
The titrant is the solution in the flask. We started with 50 mL of this solution, then we added 32 mL of the standard solution. Using the dilution formula;
M2 = 2.5 M × 32 mL/50 mL
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We can use the ideal gas law equation to find the volume of the balloon.
PV = nRT
where
P - pressure - 0.992 atm x 101 325 Pa/atm = 100 514 Pa
V - volume
n - number of moles - 8.80 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 25 °C + 273 = 298 K
Substituting these values in the equation
100 514 Pa x V = 8.80 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 217 L
volume of balloon is 217 L
You would put it on the flat side because it would be easier to build on flat ground than a steep slope
Answer:
The answer to your question is P = 0.18 atm
Explanation:
Data
mass of O₂ = 0.29 g
Volume = 2.3 l
Pressure = ?
Temperature = 9°C
constant of ideal gases = 0.082 atm l/mol°K
Process
1.- Convert the mass of O₂ to moles
16 g of O₂ -------------------- 1 mol
0.29 g of O₂ ---------------- x
x = (0.29 x 1)/16
x = 0.29/16
x = 0.018 moles
2.- Convert the temperature to °K
Temperature = 9 + 273 = 282°K
3.- Use the ideal gas law ro find the answer
PV = nRT
-Solve for P
P = nRT/V
-Substitution
P = (0.018 x 0.082 x 282) / 2.3
-Simplification
P = 0.416/2.3
-Result
P = 0.18 atm