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Ede4ka [16]
3 years ago
12

What is the difference between a pure solvent and a solution? Do they have the same physical properties?

Chemistry
1 answer:
pychu [463]3 years ago
5 0

Answer:

The physical properties of a solution are different from those of the pure solvent. ... Colligative properties are those physical properties of solutions of nonvolatile solutes that depend only on the number of particles present in a given amount of solution, not on the nature of those particles.

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Two difference between molecular formula and molecular weight<br>please help :((​
Volgvan

Answer: Formula weight is the sum of weights of all the atoms in an empirical formula of a molecule. Molecular weight is the collection of weights of all the atoms in a molecular formula.

Explanation:

8 0
3 years ago
Crown ethers are used to complex ionic compounds (or metal ions) because the oxygen in the crown ether will complex readily with
Yuki888 [10]

Answer:

True

Explanation:

Crown ethers are macrocyclic Organic compounds having oxygen atoms inside a chian of carbon atoms.

Crown ethers are of great importance in coordination chemistry because, the lone pairs on oxygen atoms could coordinate metal ions thereby sequestering them from aqueous solutions.

5 0
3 years ago
over a 12.3 minuete period 5.13 E-3 moles of F2 gas effuses from a contaier. How many moles of CH4 gas could effuse from from th
Aleonysh [2.5K]

Answer : The moles of methane gas could be, 7.90\times 10^{-3}mol

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}

[\frac{(\frac{n_1}{t_1})}{(\frac{n_2}{t_2})}]=\sqrt{\frac{M_2}{M_1}}

where,

R_1 = rate of effusion of fluorine gas

R_2 = rate of effusion of methane gas

n_1 = moles of fluorine gas = 5.13\times 10^{-3}mol

n_2 = moles of methane gas = ?

t_1=t_2 = time = 12.3 min  (as per question)

M_1 = molar mass of fluorine gas  = 38 g/mole

M_2 = molar mass of methane gas = 16 g/mole

Now put all the given values in the above formula 1, we get:

[\frac{(\frac{5.13\times 10^{-3}mol}{12.3min})}{(\frac{n_2}{12.3min})}]=\sqrt{\frac{16g/mole}{38g/mole}}

n_2=7.90\times 10^{-3}mol

Therefore, the moles of methane gas could be, 7.90\times 10^{-3}mol

8 0
3 years ago
Multiple choice (ASAP!)
kobusy [5.1K]

Answer:

c

Explanation:

oxygen is lost electrons are added in oxidation state is decreased

7 0
3 years ago
Read 2 more answers
Calculate the molarity of 0.060 moles of sodium bicarbonate (NaHCO3) in 1500. mL of solution.
inna [77]

Answer: 0.040 mol/l

Explanation: Molarity c = n/V (Concentration)

c = 0.060 mol / 1,5 l = 0,040 mol/l

5 0
3 years ago
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