Answer:
ASA
Step-by-step explanation:
Answer:
reduce 10 qauts of 50%
Step-by-step explanation:
Answer:
a) x = 6° b) m∠B = 50°
Explanation:
(a) total angle measure of a triangle is 180°
8x + 2 + 70° + 60° = 180°
8x + 132° = 180°
8x = 180° - 132°
8x = 48°
x = 6°
(b)
m∠B = 8x + 2
m∠B = 8(6) + 2°
m∠B = 48° + 2°
m∠B = 50°
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
Answer:
There are 2 solutions x=0 x=4
Step-by-step explanation:
2 | 6-3x| +4 = 16
Subtract 4 from each side
2 | 6-3x| +4 -4= 16-4
2 | 6-3x| = 12
Divide by 2
2/2 | 6-3x| = 12/2
| 6-3x| = 6
Now set what is inside the absolute value equal to plus and minus what is on the right side
6-3x = 6 or 6-3x = -6
Subtract 6 from each side
6-6-3x = 6-6 or 6-6-3x = -6-6
-3x =0 -3x = -12
Divide by -3 on each side
-3x/-3 =0/-3 -3x/-3 = -12/-3
x =0 x=4
There are 2 solutions x=0 x=4
