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3 years ago

Why do weak acid-weak base reactions not go to completion?

Chemistry

2 answers:

dezoksy [38]3 years ago

7 0

Answer: Option (c) is the correct answer.

Explanation:

Weak acid and weak bases are the species that dissociate weakly in a solvent or water.

For example, acetic acid ( $CH_{3}COOH$ ) is a weak acid and it dissociates poorly in water.

Hence, we can say that due to weak dissociation there will less formation of hydrogen or hydroxide ions upon dissociation of weak acid or weak base. Therefore, due to lack of sufficient number of ions the reaction will not go to completion.

Thus, we can conclude that weak acid-weak base reactions not go to completion because neither a weak acid nor a weak base has a strong tendency to transfer $H^+$ ions.

vladimir2022 [97]3 years ago

4 0

Neither a weak acid nor a weak base has a strong tendency to transfer H+ ions that is why weak acid-weak base reactions not go to completion.

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What volume (in liters) of a solution contains 0.14 mol of KCl?

oksano4ka [1.4K]

Answer:

$\boxed {\boxed {\sf 0.078 \ L }}$

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

moles of solute = 0.14 mol KCl
molarity= 1.8 mol KCl/ L
liters of solution=x

Substitute these values/variables into the formula.

$1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}$

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

$\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}$

$1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl$

$1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl$

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

$\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}$

$x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}$

The units of moles of potassium chloride cancel.

$x= \frac{0.14 }{1.8 L}$

$x=0.07777777778 \ L$

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

$x \approx 0.078 \ L$

There are approximately 0.078 liters of solution.

5 0

3 years ago

What happens when carbon dioxide is passed through lime water for a long time? write with equation

Vlada [557]

Answer:

when CO2 gas is passed through lime water it turns milky due to the formation of calcium carbonate which formula is CaCO3.

Ca(OH)2+ CO2------ CaCO3

when excess of carbon dioxide is passed through calcium carbonate calcium hydrogen carbonate is formed and solution become colourless.

CaCO3+CO2------ Ca(HCO3)

5 0

3 years ago

What pressure will be exerted by 0.675 moles of a gas at 25*C if it is in a 0.750-L container?

Westkost [7]

PV=nRT

P=nRT/V

P=[(0.650mol)(0.08206)(298K)]/(0.750L)=21.2atm

6 0

3 years ago

Please help me I will give a brainleist to anyone who answers

tekilochka [14]

Answer:

Explanation:

4 0

2 years ago

For a reaction at equilibrium, which change can increase the rates of the forward and reverse reactions?a decrease in the concen

Monica [59]

Question requires a change resulting in an increase in both forward and reverse reactions. Now lets discuss options one by one and see there impact on rate of reactions.

1) A decrease in the concentration of the reactants:
When concentration of reactant is decreased it will shift the equilibrium in Backward direction, so resulting in increasing the backward reaction and decreasing the forward direction. Hence, this option is incorrect.

2) A decrease in the surface area of the products:
Greater the surface Area greater is the chances of collision and greater will be the rate of reaction. As the surface area of products is decreased it will not favor the backward reaction. Hence again this statement is incorrect according to given statement.

3) An increase in the temperature of the system:
An increase in temperature will shift the reaction in endothermic side. Hence, if the reaction is endothermic, an increase in temperature will increase the rate of forward direction or if the reaction is exothermic it will increase the rate of reverse direction. Hence, this option is correct according to given statement.

4) An increase in the activation energy of the forward reaction:
An increase in Activation energy will decrease the rate of reaction, either it is forward or reverse. So this is incorrect.

Result:
Hence, the correct answer is,"An increase in the temperature of the system".

7 0

2 years ago