Answer:
Nacelle. The nacelle sits atop the tower and contains the gearbox, low- and high-speed shafts, generator, and brake.
Explanation:
When the balanced equation for this reaction is:
2Fe + 3H2O → Fe2O3 + 3H2
and according to the vapour pressure formula:
PV= nRT
when we have P is the vapor pressure of H2O= 0.121 atm
and V is the volume of H2O = 4.5 L
and T in Kelvin = 52.5 +273 = 325.5 K
R= 0.08205 atm-L/g mol-K
So we can get n H2O
So, by substitution:
n H2O = PV/RT
= (0.121*4.5)/(0.08205 * 325.5) = 0.02038 gmol
n Fe2O3 = 0.02038 * (1Fe2O3/ 3H2O) = 0.00679 gmol
Note: we get (1FeO3/3H2O) ratio from the balanced equation.
we can get the Mass of Fe2O3 from this formula:
Mass = number of moles * molecular weight
when we have a molecular weight of Fe2O3 = 159.7
= 0.00679 * 159.7 = 1.084 g
∴ 1.084 gm of Fe2O3 will produced
POH = - log [ OH⁻ ]
pOH = - log [ 1 x 10⁻⁹ ]
pOH = 9
Answer C
hope this helps!
Answer:
Please find the structure attached as an image
Explanation:
Based on the characteristics ending name (-ene) of the organic compound above, it belongs to the ALKENE GROUP. Alkenes are characterized by the possession of a carbon to carbon double bond (C=C) in their structure.
- But-3-ene tells us that the organic compound has four straight carbon atoms with the C=C (double bond) located on the THIRD carbon depending on if we count from right to left or vice versa.
- 2 methyl indicates that the methyl group (-CH3) is located as an attachment on the second carbon (carbon 2).
N.B: In the structure attached below, the counting is from the left to right (→).
Answer : The value of
at this temperature is 66.7
Explanation : Given,
Pressure of
at equilibrium = 0.348 atm
Pressure of
at equilibrium = 0.441 atm
Pressure of
at equilibrium = 10.24 atm
The balanced equilibrium reaction is,
![PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)](https://tex.z-dn.net/?f=PCl_3%28g%29%2BCl_2%28g%29%5Crightleftharpoons%20PCl_5%28g%29)
The expression of equilibrium constant
for the reaction will be:
![K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%28p_%7BPCl_5%7D%29%7D%7B%28p_%7BPCl_3%7D%29%28p_%7BCl_2%7D%29%7D)
Now put all the values in this expression, we get :
![K_p=\frac{(10.24)}{(0.348)(0.441)}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%2810.24%29%7D%7B%280.348%29%280.441%29%7D)
![K_p=66.7](https://tex.z-dn.net/?f=K_p%3D66.7)
Therefore, the value of
at this temperature is 66.7